Wiki User
∙ 2013-08-26 13:35:3066
Wiki User
∙ 2013-08-26 13:35:30Number of 7 digit combinations out of the 10 one-digit numbers = 120.
56 combinations. :)
This question needs clarificatioh. There are 4 one digit number combinations, 16 two digit combinations, ... 4 raised to the n power for n digit combinations.
The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.
It is: 9C7 = 36
Number of 7 digit combinations out of the 10 one-digit numbers = 120.
9^9 = 387420489 different digit combinations.
15
10,000
2304
56 combinations. :)
10!/3! = 604800 different combinations.
Through the magic of perms and coms the answer is 729
9!/6!, if the six different orders of any 3 digits are considered distinct combinations.
If there are no restrictions on duplicated numbers or other patterns of numbers then there are 10 ways of selecting the first digit and also 10 ways of selecting the second digit. The number of combinations is therefore 10 x 10 = 100.
This question needs clarificatioh. There are 4 one digit number combinations, 16 two digit combinations, ... 4 raised to the n power for n digit combinations.
There are 360 of them.