0
nCr = n!/r!(n-r)! = 4
I'm using the combination formula where the place of the digits is not important No if the place
for instance the combination 312 is the same as 213.
But I think you are asking for a permutation instead where the placements of the digits are also important. So it would actually be 4!/(4-3)! or 24.
In a permutation the place is significant
i.e. 312 and 213 are distinct even though they have the same 3 digits.
What else can I help you with?
How many 2 digit combinations can be made with 2 digits?
Only one.
How many 2 digit combinations can be made from 0 to 9 digits?
45 In combinations, the order of the digits does not matter so that 12 and 21 are considered the same.
How many 5 digit combinations are there in six digits?
about 1,0000000000000
How many 4 digit combinations can be made using numbers 1 2 3 4 6?
120 combinations using each digit once per combination. There are 625 combinations if you can repeat the digits.
How many three digit combinations can be made?
To find the number of three-digit combinations, we consider the digits from 000 to 999. Each digit can range from 0 to 9, giving us 10 options for each of the three digits. Therefore, the total number of three-digit combinations is (10 \times 10 \times 10 = 1,000).
How many 4 digit combinations can be made from 6 digits?
If the 6 digits can be repeated, there are 1296 different combinations. If you cannot repeat digits in the combination there are 360 different combinations. * * * * * No. That is the number of PERMUTATIONS, not COMBINATIONS. If you have 6 different digits, you can make only 15 4-digit combinations from them.
How many 6 digit combinations can be made from digits 0 to 9?
10C6 = 10*9*8*7/(4*3*2*1) = 210 combinations.
How many 4 digit combinations can be made with 4 digits?
9,000 - all the numbers between 1,000 and 9,999 inclusive. * * * * * NO. Those are PERMUTATIONS, not COMBINATIONS. Also, the question specified 4 digit combinations using 4 digits. The above answer uses 10 digits. If you start with 4 digits, you can make only 1 combination.
How many 4 digit combinations are made out 2468?
Only one: 2468. The order of the digits in a combination does not make a difference.
What combinations can you make with numbers 1 4 7 2 5 8 0?
Assuming the digits cannot be repeated, there are 7 combinations with 1 digit, 21 combinations with 2 digits, 35 combinations with 3 digits, 35 combinations with 4 digits, 21 combinations with 5 digits, 7 combinations with 6 digits and 1 combinations with 7 digits. That makes a total of 2^7 - 1 = 127: too many for me to list. If digits can be repeated, there are infinitely many combinations.
If using numbers 1 through 9 how many different 4 digit combinations can be made with no restrictions on order or repeats?
Each digit can appear in each of the 4 positions. There are 9 digits, therefore there are 9⁴ = 6561 such combinations.
How many 9 digit combinations are there from 1 to 20-?
There are 167960 9 digits combinations between numbers 1 and 20.
