There are 9C3 = 84 combinations.
Number of 7 digit combinations out of the 10 one-digit numbers = 120.
It is: 9C7 = 36
66
There are 1140 five digit combinations between numbers 1 and 20.
There are 1,120,529,256 combinations.
There are 9C3 = 84 combinations.
6 of them.
Only one.
How many four digit combinations can be made from the number nine? Example, 1+1+2+5=9.
120 combinations using each digit once per combination. There are 625 combinations if you can repeat the digits.
There are 15180 combinations.
"There are 10,000 different combinations"-Hey nick! love dave and jalp
If the 6 digits can be repeated, there are 1296 different combinations. If you cannot repeat digits in the combination there are 360 different combinations. * * * * * No. That is the number of PERMUTATIONS, not COMBINATIONS. If you have 6 different digits, you can make only 15 4-digit combinations from them.
10 Combinations (if order doesn't matter). 3,628,800 Possiblilities (if order matters).
To calculate the number of 6-digit combinations using 20 numbers, you can use the formula for combinations, which is nCr = n! / r!(n-r)!. In this case, n = 20 (the total number of numbers) and r = 6 (the number of digits in each combination). Plugging these values into the formula gives us 20C6 = 20! / 6!(20-6)! = 38,760 unique 6-digit combinations that can be formed using 20 numbers.
Number of 7 digit combinations out of the 10 one-digit numbers = 120.