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Q: How many 4 digit numbers can be formed by the digits 1 2 3 4 using each digit only once?

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There are 60480 numbers.

There are 900 of them.

More than one

27

Using the digits of 1345678, there are 210 three digit numbers in which no digit is repeated.

48 of them if digits may not be repeated. 100 if they can.

6

I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24

27 if the digits can be repeated. 6 if not.

Possible solutions - using your rules are:- 11,13,17,31,33,37,71,73 &77

the largest five digit number that can be formed using the digits 7 and 9 is 97,000

151200 numbers.

2,401

There are 25 such numbers.

There are 2000 such numbers.

Four digit numbers span from 1000 to 9999. This totals (9999-1000) +1 = 9000 different four digit numbers

There are twelve possible solutions using the rule you stated... 13,14,17,31,34,37,41,43,47,71,73 & 74

9*8*7 = 504 of them.

9630

It is 415968.

99999

2520 numbers.

If they can be repeated, 343 different numbers. If they can be used once each, there are only 210.

You have 2 options for the first digit, 2 options for the second digit, etc. ... In total, that gives you 210 combinations.

You can select 9 numbers for the first digit, 8 numbers for the second digit, and 7numbers for the third digit; so 504 (e.g. 9*8*7) different three digit numbers can be written using the digits 1 through 9.