24 different numbers.
27
More than one
If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.
6
Possible solutions - using your rules are:- 11,13,17,31,33,37,71,73 &77
There are 60480 numbers.
27
More than one
48 of them if digits may not be repeated. 100 if they can.
If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.
6
Possible solutions - using your rules are:- 11,13,17,31,33,37,71,73 &77
To form a three-digit number using the digits 1-7, we can choose any of the 7 digits for each of the three places (hundreds, tens, and units). Therefore, the total number of 3-digit combinations can be calculated as (7 \times 7 \times 7), which equals 343. Thus, there are 343 different three-digit numbers that can be formed using the digits 1-7.
Using the digits of 1345678, there are 210 three digit numbers in which no digit is repeated.
I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24
None. Nine digit number cannot be formed using only five digits 1,2,3,4,5 in the case none of the digits can repeat. -------- Egad! I misread the question, apologies to the questioner. And thanks to Miroslav.
151200 numbers.