256
Each "place holder" if you will, may contain 4 numbers. So it is 4x4x4x4
With 123 digits you can make 123 one-digit numbers.
Not sure what a "didget" is. It is possible to make 18 5-digit numbers.
24
There are no three didgit numbers but there are 63 three digit numbers.
24 = 4*3*2*1
With 123 digits you can make 123 one-digit numbers.
Not sure what a "didget" is. It is possible to make 18 5-digit numbers.
24
12,13,14 21,23,24 31,32,34 43,42,41 12 two-digit numbers
There are no three didgit numbers but there are 63 three digit numbers.
24 = 4*3*2*1
1
19 times10,11 (is 2),12,13,14,15,16,17,18,19,21,31,41,51,61,71,81 and 91
If you want 4-digit numbers, there are 24 of them.
9
1,956 different numbers can be made from 6 digits. You can calculate this by using the permutation function in a summation function, like this: Σ6k=1 6Pk = 6P1+6P2+...+6P5+6P6 What this does is calculate how many 1 digit numbers you can make from 6 digits, then how many 2 digit numbers can be made from 6 digits and adds the amounts together, then calculates how many 3 digit numbers can be made and adds that on as well etc.
The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.