Q: How many 2-digit numbers contain digit 1?

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There are 6804 such numbers.

To find the total number of seven-digit numbers that contain the number seven at least once, we can use the principle of complementary counting. There are a total of 9,999,999 seven-digit numbers in total. To find the number of seven-digit numbers that do not contain the number seven, we can count the number of choices for each digit (excluding seven), which is 9 choices for each digit. Therefore, there are 9^7 seven-digit numbers that do not contain the number seven. Subtracting this from the total number of seven-digit numbers gives us the number of seven-digit numbers that contain the number seven at least once.

27: 077,177,277,377,477,577,677,877,977,717,727,737,747,757,767,777,787,797

well, i think if you use this you can find out. A = 1-9 ,B = 0-9 , C = 0-9 , D = 0-9 , E = 0-9 for 2digit numbers = A A for 3 digit numbers = A B A for 4 digit numbers = A B B A and so on till you get to for 8 digit numbers = A B C D D C B A for 9 digit numbers = A B C D E D C B A and last for 10 digit number = A B C D E E D C B A this should work...

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17

There are 9000 4-digit numbers. 8*9*9*9 = 5832 of them do not contain a 5 The remaining 3168 contain a 5.

-2

It would help to know which digit. 0 appears in 9 numbers and each of the others in 18 numbers.

-5

-5

252

There are 6804 such numbers.

The pages of a book are numbered from 1 to 128. How many page numbers contain the digit 6?

648

874

252