infinite. not kidding.
* * * * *
Not kidding but NOT CORRECT either!
There are 10!/(5!*5!) combinations where n! = 1*2* ... *n
10*9*8*7*6/(5*4*3*2*1) = 252 combinations.
6,720 combinations.
There is only one possible combination as a combination is the same no matter what the order is. There are 120 permutations, which is where the order does matter.
how many times gerater is the underlined digit 5 in 365,486,201 than the digit 5
There are 600 5-digit numbers divisible by 150.
There are 9000 of them.
There are 126 different 5 digit combinations. Note that the combination 12345 is the same as the combination 45312.
6,720 combinations.
There is only one possible combination as a combination is the same no matter what the order is. There are 120 permutations, which is where the order does matter.
how many times gerater is the underlined digit 5 in 365,486,201 than the digit 5
50 to the 5th power.156,250 combination.
120
There are 600 5-digit numbers divisible by 150.
125
How many two digit number are divisible by 5
There are 90000 5-digit numbers.
There are 9 1-digit numbers and 16-2 digit numbers. So a 5 digit combination is obtained as:Five 1-digit numbers and no 2-digit numbers: 126 combinationsThree 1-digit numbers and one 2-digit number: 1344 combinationsOne 1-digit numbers and two 2-digit numbers: 1080 combinationsThat makes a total of 2550 combinations. This scheme does not differentiate between {13, 24, 5} and {1, 2, 3, 4, 5}. Adjusting for that would complicate the calculation considerably and reduce the number of combinations.
There are 9000 of them.