There are 9000 of them.
Wiki User
∙ 9y agoThere are 600 5-digit numbers divisible by 150.
None. 3 digit numbers are not divisible by 19 digit numbers.
There are 5 numbers which can make the 3 digit numbers in this example. Therefore each digit in the 3 digit number has 5 choices of which number can be placed there. Therefore number of 3 digit numbers = 5 x 5 x 5 = 125
4
There are 9000 4-digit numbers. 8*9*9*9 = 5832 of them do not contain a 5 The remaining 3168 contain a 5.
There are five such numbers.
With a total of 90,000 five digit numbers, we can conclude that there is 45,000 EVEN five digit numbers.
There are 90000 5-digit numbers.
120
There are 126 of them.
a lot
There are 9 1-digit numbers and 16-2 digit numbers. So a 5 digit combination is obtained as:Five 1-digit numbers and no 2-digit numbers: 126 combinationsThree 1-digit numbers and one 2-digit number: 1344 combinationsOne 1-digit numbers and two 2-digit numbers: 1080 combinationsThat makes a total of 2550 combinations. This scheme does not differentiate between {13, 24, 5} and {1, 2, 3, 4, 5}. Adjusting for that would complicate the calculation considerably and reduce the number of combinations.
99
8000
The first digit can have 5 possible numbers, the second digit can have 4, the third 3, the fourth 2. 5
There are 5! = 120 such numbers.
There are 5460 five digit numbers with a digit sum of 22.