The number of combinations, denoted by 11C6 is 11!/[6!*(11-6)!]
= 11*10*9*8*7/(5*4*3*2*1) = 462
There are 840 4-digit combinations without repeating any digit in the combinations.
Without repeating, 4. With repeating, 8.
There are 35C4 = 35*34*33*32/(4*3*2*1) = 52,360 combinations.
11
To find all the combinations of the numbers 1204 without repeating any number, we can use the formula for permutations without repetition. There are 4 digits in the number 1204, so there are 4 factorial (4!) or 24 possible combinations. These combinations would include 1204, 1240, 1024, 1042, 1402, 1420, 2104, 2140, 2014, 2041, 2401, 2410, 4012, 4021, 4102, 4120, 4201, 4210, 1024, 1042, 1204, 1240, 1402, 1420.
There are only five combinations: 1234, 1235, 1245, 1345 and 2345.
6
The number of combinations of 4 numbers that can be made from a set of 36 numbers without repeating any numbers is calculated using the combination formula. The formula for combinations is nCr = n! / r!(n-r)!, where n is the total number of options and r is the number of selections. In this case, n = 36 and r = 4. Therefore, the number of combinations is 36! / 4!(36-4)! = 36! / 4!32! = (36 x 35 x 34 x 33) / (4 x 3 x 2 x 1) = 58905 combinations.
Without repetition, just one. In a combination the order of the numbers is irrelevant.
There are 46C5 = 46*45*44*43*42/(5/4/3/2/1) = 1,370,754 of them and I am not stupid enough to try and list them. You are welcome to try, though.
5040
1,023,456,789