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The answer is 26C5 = 26*25*24*23*22/(5*4*3*2*1) = 65,780

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Q: How many 5 number combinations there are from 1 to 26?
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How many 5-number combinations are there for numbers 1-26?

To calculate the number of 5-number combinations from a pool of 1-26, we use the combination formula, which is nCr = n! / r!(n-r)!. In this case, n = 26 (numbers 1-26) and r = 5 (5-number combinations). Plugging these values into the formula, we get 26C5 = 26! / 5!(26-5)! = 26! / 5!21!. Simplifying this further, we get 2625242322 / 54321 = 65,780 different 5-number combinations.


How many 3 number combinations 1 to 6?

There are 6C3 = 20 such combinations.


How many 5 digit number combinations from 1 to 60slide1?

There are 5,461,512 such combinations.


How many 3 letter combinations?

Oh, dude, there are like 26 letters in the alphabet, right? So, for each position in a 3-letter combination, you have 26 choices. That means you'd have 26 choices for the first letter, 26 for the second, and 26 for the third. So, the total number of 3-letter combinations would be 26 x 26 x 26, which is... math.


What four numbers equal 26?

How about: 1+2+3+20 = 26 out of many other combinations


How many 6 number combination are there in number 1 to 45?

There are 8145060 combinations.


How many combinations can you make with exactly 31 cents?

Precisely 1. For ANY number n, the number of combinations of n of those items is always 1.


How many combinations can you make with the numbers 2 3 6 7 and 8?

You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.


How many 12 number combinations are there in numbers 1 to 24?

There are 24C12 = 24!/[12!*12!] = 2,704,156 combinations.


How many 4 number combinations can made from 1459?

4*3*2*1 = 24 different combinations.


How many 3 digit combinations are there in 1 to 21?

I am assuming you mean 3-number combinations rather than 3 digit combinations. Otherwise you have to treat 21 as a 2-digit number and equate it to 1-and-2. There are 21C3 combinations = 21*20*19/(3*2*1) = 7980 combinations.


How many 6 number combinations are there in 1-55?

55C6 = 28,989,675