To calculate the number of 5-number combinations from a pool of 1-26, we use the combination formula, which is nCr = n! / r!(n-r)!. In this case, n = 26 (numbers 1-26) and r = 5 (5-number combinations). Plugging these values into the formula, we get 26C5 = 26! / 5!(26-5)! = 26! / 5!21!. Simplifying this further, we get 2625242322 / 54321 = 65,780 different 5-number combinations.
There are 6C3 = 20 such combinations.
There are 5,461,512 such combinations.
Oh, dude, there are like 26 letters in the alphabet, right? So, for each position in a 3-letter combination, you have 26 choices. That means you'd have 26 choices for the first letter, 26 for the second, and 26 for the third. So, the total number of 3-letter combinations would be 26 x 26 x 26, which is... math.
How about: 1+2+3+20 = 26 out of many other combinations
There are 8145060 combinations.
Precisely 1. For ANY number n, the number of combinations of n of those items is always 1.
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
There are 24C12 = 24!/[12!*12!] = 2,704,156 combinations.
4*3*2*1 = 24 different combinations.
I am assuming you mean 3-number combinations rather than 3 digit combinations. Otherwise you have to treat 21 as a 2-digit number and equate it to 1-and-2. There are 21C3 combinations = 21*20*19/(3*2*1) = 7980 combinations.
55C6 = 28,989,675