It is: 55C6 = 28,989,675
Assuming you cannot repeat a single number within the combinations, there are a total of 56 x 55 x 54 x 53 x 52 x 51 = 23377273920 combinations of 56 numbers.
There are 11C2 = 11*10/(2*1) = 55 combinations.
There are 56C5 = 56*55*54*53*51/(5*4*3*2*1) = 3,819,816 combinations.
55C6 = 28,989,675
55C6 = 28,989,675
just intrested in the number combinations * * * * * Number of combinations = 56C6 = 56*55*54*53*52*51/(6*5*4*3*2*1) = 32,468,436
The number of combinations is nCr = (59*58*57*56*55)/(5*4*3*2*1) = 5006386
Assuming you cannot repeat a single number within the combinations, there are a total of 56 x 55 x 54 x 53 x 52 x 51 = 23377273920 combinations of 56 numbers.
There are 11C2 = 11*10/(2*1) = 55 combinations.
There are 56C5 = 56*55*54*53*51/(5*4*3*2*1) = 3,819,816 combinations.
59! / 54! = 59 * 58 * 57 * 56 * 55 = 600766320
Number of combinations = 59*58*57*56*55/(5*4*3*2*1) = 5006386.
55C6 = 28,989,675
55C6 = 28,989,675
26 = 64 combinations, including the null combination - which contains no numbers.
combinations of 55If there is not repetition in numbers used......55 x 54 x 53 x 52 x 51 * * * * *No. That is the number of permutations. For combinations the order of the number does not matter so that 1,2,3,4,5 is the same as 1,3,2,4,5 or 1,4,2,3,5 etc.There are 5*4*3*2*1 = 120 such orderings for every set of 5 numbers. So the correct answer is55*54*53*52*51 / 120 = 3478761
61