The conversion factor between atoms and moles is Avogadro's number: 6.02 x 1023 "things" / mole
To convert moles to atoms:
atoms B = 2.47 mol B6.02 x 1023 atoms B = 1.49E+24 atoms B
1 mol B
Multiply by atoms per mole. Moles cancel out.
Let the two numbers be represented by 'a' and 'b'. Then, a + b = 645 And a - b = 151............adding these two eqations together gives :- 2a = 796 : a = 398..........and b = 645 - 398 = 247 (or b = 398 - 151 = 247).
jj
Infinitely many. Let B be any number less than 6 cm, and let L = 12-B cm. Then the perimeter of the rectangle, with length L and breadth B, is 2*[L+B] = 2*[(12-B)+B] = 2*12 = 24 cm. There are infinitely many possible values for B, between 0 and 6 and so there are infinitely many possible rectangles.
There are infinitely many such rectangles.Consider any positive number, B which is less than 6 gronks. Let L be 12-B gronnks. Then L > 6 and so no ordered pairs (L, B) will be equal to a (B, L).Any rectangle with length L gronks and breadth B gronks will have a perimeter of 2*(L+B) = 2*12 = 24 gronks.Since the choice of B was arbitrary there are infinitely many choices for B and since each value of B gives a unique rectangle, there are infinitely many rectangles.As many as you want.
The letter B has one set of line symmetry.The top of the B and the bottum.
a moles (b moles/a moles) = b moles
15.8 mol B = 9.51 X 1024 atoms.15.8 mol (6.02 X 1023/ 1 mol) = 9.5116 X 1024
a. number of atoms = mass / molar mass x avagadros number 21/16x6.02x1023=7.9x1023 atoms b. number of atoms = moles x avagadros number 0.812x6.02x1023=4.89x1023 atoms as there is 1 O atom in each molecule of MgO, there are 4.89x1023 atoms of Oxygen. c. if there are 3.2x1022 molecules and 6 oxygen atoms in each molecule then: (3.2x1022)x6=1.92x1023 Oxygen atoms.
Well, there are 140 grams of 2Cl2 in one mole of it. You take the atomic mass and find how many atoms and multiply them together. Chlorine has an atomic mass of about 35, so multiply by four b/c there are four Cl atoms in 2Cl2 .
There is no direct relationship between atoms of boronand grams of boron. Use Avogadro's number to convert atoms to moles, and the atomic mass to convert moles to grams.Since you are converting from atoms B, this goes in the denominator (on the bottom) of the first factor. You want to end up in units of grams of B, so this goes in the numerator (on the top) of the last factor.atoms B1.00 mole B10.8 gram = g B6.02E+23 atom B1.00 mole BNote that the units atoms boron "cancel out" in the first factor and you are left in units of moles. Moles cancel outin the second factor and the final units are grams boron.
Each mole of boron atoms has a mass of 10.811 grams, as indicated by the gram atomic mass or weight of boron. Therefore, 585 moles has a mass of about 6.32 X 103 grams, to the same number of significant digits as 585.
Boron trifluoride is BF3. So each mole of BF3 contains 1 moles of boron (B) and 3 moles of fluorine (F). Thus, 3 moles of BF3 contains NINE moles of fluorine.
The answer is B, 8.0 x 10^1 There are 6.023 x 10^23 atoms in one mole, of any substance. So simply divide 4.8 x 10^25 by 6.023 x 10^23, to get about 79.69 which if you convert into scientific notation, is about 8.0 x 10^1 the answer for me was A but that's on novanet
The atomic mass of B is 10.8Amount of B = mass of pure sample/molar mass = 31.78/10.8 = 2.94mol There are 2.94 moles of the element boron in a 31.78g pure sample.
2
1.7 mol 1.7 mol
To answer that question we need a reaction, for example I will use this one. 2 A + 4 B --> 2 AB2 Imagine having 10 moles of A and 100 moles of B Once your 10 moles of A have been used up (along with 20 moles of B), you will be stuck with 80 B, without A, it will not react. Therefor it is limited (in this case) by the amount of A.