There are infinitely many such rectangles.
Consider any positive number, B which is less than 6 gronks. Let L be 12-B gronnks. Then L > 6 and so no ordered pairs (L, B) will be equal to a (B, L).
Any rectangle with length L gronks and breadth B gronks will have a perimeter of 2*(L+B) = 2*12 = 24 gronks.
Since the choice of B was arbitrary there are infinitely many choices for B and since each value of B gives a unique rectangle, there are infinitely many rectangles.
As many as you want.
There are infinitely many such rectangles.
Consider any positive number, B which is less than 6 gronks. Let L be 12-B gronnks. Then L > 6 and so no ordered pairs (L, B) will be equal to a (B, L).
Any rectangle with length L gronks and breadth B gronks will have a perimeter of 2*(L+B) = 2*12 = 24 gronks.
Since the choice of B was arbitrary there are infinitely many choices for B and since each value of B gives a unique rectangle, there are infinitely many rectangles.
There is an infinite number that can have that perimeter
thare is only 1 differint rectangles
Depends what you are drawing on.
There are three possibilities.. 1 x 12... 2 x 6 & 3 x 4
Infinitely many. Select any number, L, such that 12 < L < 24. Let W = 24 - L. Then a rectangle with sides of length L cm and width W cm will have a perimeter of 48 cm. And since the choice of L was arbitrary, there are infinitely many possible values of L and thence infnitely many rectangles.
Infinite amounts.
There is an infinite number that can have that perimeter
There would be an infinite number of rectangles possible
thare is only 1 differint rectangles
perimeter = 2 (b+h) = 20 there are an infinite number of rectangles that meet the requirement
the answer is 12
Depends what you are drawing on.
There are three possibilities.. 1 x 12... 2 x 6 & 3 x 4
Infinitely many. Select any number, L, such that 12 < L < 24. Let W = 24 - L. Then a rectangle with sides of length L cm and width W cm will have a perimeter of 48 cm. And since the choice of L was arbitrary, there are infinitely many possible values of L and thence infnitely many rectangles.
I don't understand why there are so many questions about rectangles' perimeter. You just add the length and the width and double your answer....
It depends what units you use for each side ! A 1cm x 15cm rectangle has a perimeter of 16cm. So does a 2cm x 4cm one ! If you start using millimetres, there are many more possibilities !
The only one I can think of is a square, where Length=Width=4.