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There are infinitely many such rectangles.
Consider any positive number, B which is less than 6 gronks. Let L be 12-B gronnks. Then L > 6 and so no ordered pairs (L, B) will be equal to a (B, L).
Any rectangle with length L gronks and breadth B gronks will have a perimeter of 2*(L+B) = 2*12 = 24 gronks.
Since the choice of B was arbitrary there are infinitely many choices for B and since each value of B gives a unique rectangle, there are infinitely many rectangles.
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BeauThere are infinitely many such rectangles.
Consider any positive number, B which is less than 6 gronks. Let L be 12-B gronnks. Then L > 6 and so no ordered pairs (L, B) will be equal to a (B, L).
Any rectangle with length L gronks and breadth B gronks will have a perimeter of 2*(L+B) = 2*12 = 24 gronks.
Since the choice of B was arbitrary there are infinitely many choices for B and since each value of B gives a unique rectangle, there are infinitely many rectangles.
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How many rectangles have a perimeter of 36 cm?
There is an infinite number that can have that perimeter
How many rectangles have the same area and perimeter of 18?
thare is only 1 differint rectangles
How many rectangles each having a perimeter of 36 cm can be drawn?
Depends what you are drawing on.
How many different rectangles can you make with a perimeter of 12 units?
There are three possibilities.. 1 x 12... 2 x 6 & 3 x 4
How many different rectangles have a perimeter of 48cm?
Infinitely many. Select any number, L, such that 12 < L < 24. Let W = 24 - L. Then a rectangle with sides of length L cm and width W cm will have a perimeter of 48 cm. And since the choice of L was arbitrary, there are infinitely many possible values of L and thence infnitely many rectangles.
