We'll say 9 cuts.
no, 75 is not a cube. The small cubes are 0, 1,8,27,64,125,.. which are the cubes of 0,1,2,3,4, and 5 respectively.
1003 = 106 = 1,000,000: since 100 centimeters are required to equal one meter, the larger cube is scaled up by 100 in each of its three dimensions compared to the small cubes specified.
A Cube.
6
The probability cannot be 625 since, by definition, it must be a number in the range [0, 1].
23 = 8
You cannot. And not all number cubes have the numbers 1-6 on them. For example, a doubling cube for backgammon.You cannot. And not all number cubes have the numbers 1-6 on them. For example, a doubling cube for backgammon.You cannot. And not all number cubes have the numbers 1-6 on them. For example, a doubling cube for backgammon.You cannot. And not all number cubes have the numbers 1-6 on them. For example, a doubling cube for backgammon.
no, 75 is not a cube. The small cubes are 0, 1,8,27,64,125,.. which are the cubes of 0,1,2,3,4, and 5 respectively.
Volume of 1 cm cube = 1 cubic cm (cc) Volume of 4 cm cube = 4*4*4 = 64 cc So number of unit cubes required = 64
Edge of the larger cube = 32 cm Volume of the larger cube = (32 cm)3 = 32768 cm3 Edge of the smaller cube = 4 cm Volume of the smaller cube = (4 cm)3 = 64 cm3 Since the smaller cubes are cut from the larger cube, volume of all of them will be equal to that of the larger cube. ∴ Total number of smaller cubes × Volume of the smaller cube = Volume of the larger cube ⇒ Total number of smaller cubes = Volume of the larger cube ÷ Volume of the smaller cube ⇒ Total number of smaller cubes = 32768 ÷ 64 = 512 Thus, 512 smaller cubes can be cut from the larger one.
1729 is the smallest number that can be expressed in two ways as the sum of two cubes.[12cube+9cube] * * * * * ... two positive cubes. 12 cube + 1 cube and 10 cube + 9 cube.
Assuming that the cubes are 1x1x1, there will be one thousand cubes in the larger cube.
1003 = 106 = 1,000,000: since 100 centimeters are required to equal one meter, the larger cube is scaled up by 100 in each of its three dimensions compared to the small cubes specified.
Use the information you're given, in conjunction with the properties of cubes, to find the required quantity.
8
A Cube.
If I understand the question correctly, you want the probability of each cube showing an odd number. If the number cubes are fair, then the answer is 1/4.