8
7
positive combinations:14 positive combinations not counting the same one just flipped:7 combinations including negatives: infinate
If you have 12 possible numbers with multiple combinations then you should start out with making all the possible combinations; you will find theyre 20. Theyre four numbers out of the twleve that can be divisible by three; 3, 6, 9, and 12. There are 7 combinations where the combinations can equal those four numbers. So the odds of getting a sum divisible by three is 7/20.
Assuming the digits cannot be repeated, there are 7 combinations with 1 digit, 21 combinations with 2 digits, 35 combinations with 3 digits, 35 combinations with 4 digits, 21 combinations with 5 digits, 7 combinations with 6 digits and 1 combinations with 7 digits. That makes a total of 2^7 - 1 = 127: too many for me to list. If digits can be repeated, there are infinitely many combinations.
7*3*4 = 84 combinations.
7
To write the sum of a number k and 7, you would use the mathematical expression k + 7. This expression represents adding the value of k to 7. In algebraic terms, this is known as an addition operation where k is the addend and 7 is the other addend. The result of this addition operation would give you the sum of k and 7.
positive combinations:14 positive combinations not counting the same one just flipped:7 combinations including negatives: infinate
The probability that the sum of two dice is 7 is 6 in 36, or 1 in 6.Of all the combinations, this is the one with the highest probability.
Te probability of rolling a sum of 7 with two fair dice is 6 in 36, or 1 in 6, or about 0.1667.Of all the possible combinations of two dice, the sum of 7 has the highest probability, with the other combinations decreasing down to 2 and 12, with probabilities of 1 in 36, or about 0.0278.
If you have 12 possible numbers with multiple combinations then you should start out with making all the possible combinations; you will find theyre 20. Theyre four numbers out of the twleve that can be divisible by three; 3, 6, 9, and 12. There are 7 combinations where the combinations can equal those four numbers. So the odds of getting a sum divisible by three is 7/20.
Assuming the digits cannot be repeated, there are 7 combinations with 1 digit, 21 combinations with 2 digits, 35 combinations with 3 digits, 35 combinations with 4 digits, 21 combinations with 5 digits, 7 combinations with 6 digits and 1 combinations with 7 digits. That makes a total of 2^7 - 1 = 127: too many for me to list. If digits can be repeated, there are infinitely many combinations.
It depends on the sizes of the combinations. For example, there is only one combination of 7 things out of 7, but there are 21 combinations of two items.
7*3*4 = 84 combinations.
There are 8*7/(2*1) = 28 combinations.
If it is 7 object out of 7, then just 1.
There are 7C4 = 7!/(4!*3!) = 7*6*5/(3*2*1) = 35 combinations.