There are 7C4 = 7!/(4!*3!) = 7*6*5/(3*2*1) = 35 combinations.
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You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
There are 15 combinations.
There are 35C4 = 35*34*33*32/(4*3*2*1) = 52,360 combinations.
16
This question needs clarificatioh. There are 4 one digit number combinations, 16 two digit combinations, ... 4 raised to the n power for n digit combinations.