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Power (P), in Watts, is equal to the Voltage (V), in Volts, multiplied by the Current (I), in Amperes.

P=V*I

Using Algebra to solve for the Current (Amps) that are required:

I=P/V

Therefore: 2000 Watts / 12 Volts = ~167 Amps

Please note, that this is for a 100% efficient inverter. If the inverter is 90% efficient the actual draw would be:

Iideal*(1+(1-(%Efficiency/100)))=Iactual

167 Amps*(1+(1-(90/100)))=Iactual

167 A * (1+(1-0.9))=Iactual

167 A * (1+(0.1))=Iactual

167 A * (1.1)=Iactual

183 A = Iactual

The continuous current draw for a 90% efficient power inverter, operating from a 12V DC source, out putting 2000W at 120V AC, is 183 Amps.

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16y ago
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13y ago

Assuming no loss in the circuitry:

Amps * Volts = Watts

Amps * 12 = 400

Amps = 400 / 12

Amps = 33.33333...

BUT

inverts build heat, and that heat wastes electrical energy

Your inverter is probably drawing (at full load) somewhere near 40 amps.

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12y ago

83.3333 Amps

<<>>

The answer to this question, how many watts are drawn from the battery, is dependant upon what the amperage of the connected load is. A 1000W rated inverter is the maximum amount of connected wattage load that can be used from the inverter. W = A x V.

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Q: How many amps does a 400w inverter draw from a 12 volt system?
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