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There are 5 letters: a c e f and h.If the letters can be repeated, then there are five possibilities for each space in the four-letter arrangement. The number of arrangements then is:5*5*5*5 = 54 = 625.
The number is 26*25*24 = 15600.
There are 12 two letter arrangements of the letters in PARK.
There are 172 different arrangements.
You have eight letters to work with, and can use any four of them, but only once per combination. That means that the total number of possible combinations you can make is: 8! / (8 - 4)! = 8! / 4! = 8 * 7 * 6 * 5 = 1680 So there are 1680 possible combinations.
Five
120
There are 5 letters: a c e f and h.If the letters can be repeated, then there are five possibilities for each space in the four-letter arrangement. The number of arrangements then is:5*5*5*5 = 54 = 625.
If you pick from each of the possible letters at each stage, then there are 5 possible options for the first letter. Then there are 4 possible options for the second. Then there are 3 possible options for the 3rd and so on. This leaves us with 5x4x3x2 = 120 different arrangements. However, each arrangement has been counted twice, as it doesn't matter which way around the Os go. So to get the true answer, we need to divide by 2. 120/2 = 60, and therefore the number of different arrangements of the letters in the word COLOR is 60.
The number is 26*25*24 = 15600.
24 The first letter can be any of the 4. The second can be any of the remaining 3. The third, either remaining, and the last, the only remaining one. This means there are 4*3*2*1=24 different arrangements.
There are 12 two letter arrangements of the letters in PARK.
It depends on the letters and also on the words that have been placed on the board.
There are 172 different arrangements.
You have eight letters to work with, and can use any four of them, but only once per combination. That means that the total number of possible combinations you can make is: 8! / (8 - 4)! = 8! / 4! = 8 * 7 * 6 * 5 = 1680 So there are 1680 possible combinations.
The number of arrangements of the letters PARTY, if the first letter must be an A is the same as the number of arrangements of the letters PRTY, and that is 4 factorial, or 24.
the arrangements occur. if there are two of the same letter then 12 all different letters then 24 three letters the same then 5 four letters the same then 1