The number of arrangements of the letters PARTY, if the first letter must be an A is the same as the number of arrangements of the letters PRTY, and that is 4 factorial, or 24.
The best way to think of this is how many options there are for each letter. There are 7 possibilities for the first letter. Then there are 6 possibilities (out of the remaining letters) for the second latter. Then 5 possibilities for the next, and so on. The total number of possibilities will be 7x6x5x4x3x2x1, which equals 5,040. So there are 5,040 different ways to arrange 7 letter words.
six each of the three first letters has the other two alternating so 3 x 2 = 6 APE AEP PAE PEA EAP EPA
The first letter can be any one of 22. For each of these ...The second letter can be any one of the remaining 21. For each of these ...The third letter can be any one of the remaining 20.So the number of different 3-letter line-ups is (22 x 21 x 20) = 9,240.That's the answer if you care about the sequence of the letters, i.e. if you call ABC and ACB different.If you don't care about the order of the 3 letters ... if ABC, ACB, BAC, BCA, CAB, and CBA are allthe same to you, then there are six ways to arrange each group of 3 different letters.Then the total number of different picks is (9,240/6) = 1,540.
150
Word 1) 'math' has one vowel letter among a total of 4 letters. The probability of randomly selecting the vowel letter 'a' is P(v) = 1/4. Word 2) 'jokes' has two vowel letters among a total of 5 letters. The probability of randomly selecting a vowel letter is P(v) = 2/5. The probability of randomly selecting a vowel letter from the first word and a vowel letter from the second word is: P(v1,v2) = 1/4 (2/5) = 2/20 = 1/10 = 0.10 = 10.0%
Given two letters, there are two ways to arrange them; first then second, or second then first. The way the question is worded, the other letters of the word do not matter.
Consider "qu" to be a single letter and then you have 4 letters to arrange in 4 slots. For the first slot you have 4 choices, the next you have 3, and so on. So the number of ways is 4*3*2*1 = 24.
To have mechanical clearance between the striker arms to which the various letters are attached.
If all the letters are unique in the set, there are 6 choices for the first letter, 5 for the second letter, 4 for the third letter, etc. This results in 6 X 5 X 4 X 3 X 2 = 720 arrangements. If some of the six letters are duplicated, there will be fewer distinct arrangements.
The best way to think of this is how many options there are for each letter. There are 7 possibilities for the first letter. Then there are 6 possibilities (out of the remaining letters) for the second latter. Then 5 possibilities for the next, and so on. The total number of possibilities will be 7x6x5x4x3x2x1, which equals 5,040. So there are 5,040 different ways to arrange 7 letter words.
The first letter can be any one of the 6 letters. For each of those . . .The second letter can be any one of the remaining 5 letters. For each of those . . .The third letter can be any one of the remaining 4 letters. For each of those . . .The fourth letter can be any one of the remaining 3 letters. For each of those . . .The fifth letter can be any one of the remaining 2 letters.The total number of different ways they can be arranged is (6 x 5 x 4 x 3 x 2) = 720 .
4 choices for the first letter 3 choices for the second, once the first has been chosen 2 choices for the third, once the first and the second have been chosen 1 for the last So it's 4x3x2x1 = 24
Some seven letter words with the first and sixth letters the same are:abysmalaccrualacrobatadmiralalmanacanagramangulararrivalartisanarsenalcapricechalicecollectcompactconcoctconductconnectcontactconvictcorrectcornicecrevicedecidedegradeearlierepithetescapeefalsifyfortifygarbagegeologyhealthyidioticillicitimperilinertiaingraininhabitinheritinhibitinsulininvalidkaraokelegallylegiblylightlylikablelocallylooselylovableloyallyluckilymacramenirvananothingoctagonopinionoutlookovationoxbloodperhapspreceptpreemptrampartrapturerectoryrequirerestorerevelryrivalryrhubarbrupturesadnesssarcasmselfishsoloiststylishsubsistsuccesssucrosesuggestsupposesurmisesurpasssynapsetaffetatermitethirstythriftytributetrinityuraniumwillowy
There are 26 letters in the alphabet.The first letter is A and it ends with Z.
adele
The first letter of bandits password is M and his pass is four letters!
hymn