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How many arrangements of the letters MATH are possible if each letter can be used only once in each arrangement?
Wiki User
∙ 13y ago
24
The first letter can be any of the 4. The second can be any of the remaining 3. The third, either remaining, and the last, the only remaining one. This means there are 4*3*2*1=24 different arrangements.
Wiki User
∙ 13y ago
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How many different arrangements can be formed using the letters in the word ABSOLUTE if each letter is used only once?
That's eight letters, so: 8! = 40320 different arrangements. n! means "factorial", and the expression expands to n*(n - 1)*(n - 2) ... * 2 * 1
How many visually different arrangements can be made from the letters of the word giggling?
Answer: 840. If all the letters in "giggling" were different, there would be 8*7*6*5*4*3*2*1=40320 arrangements: 8 ways to choose the first letter in an arrangement, 7 ways to choose the second, 6 ways to choose the third, and so on. But there are two problems with that: the g's and the i's. Let's start with the i's. There are two of them, which can be switched in any arrangement without changing how it looks. So when we counted 40320 arrangements above, we counted each arrangement twice, once for each order of the i's. So we should divide 40320 by 2, to get 20160. The g's are a similar idea, except there are 4 of them. So there are 4*3*2*1 or 24 visually identical ways to order the g's. That means we counted each truly different arrangement 24 times: one for each such visually identical order of the g's. So the number 20160 is inflated by a factor of 24, and we should divide it by 24, getting 840.
How many 3-letter code words are possible using the first 8 letters of the alphabet if adjacent letters cannot be the same?
The answer would be 210
How many different arrangements of 7 letters can be formed from the letters in the word ALGEBRA?
The number of 7 letter permutations of the word ALGEBRA is the same as the number of permutation of 7 things taken 7 at a time, which is 5040. However, since the letter A is duplicated once, you have to divide by 2 in order to find out the number of distinct permutations, which is 2520.
How many passwords are possible using the twenty-six uppercase letters of the alphabet without repeating letters for a 3 letter password?
26 x 25 x 24 = 15600
How many five-letter arrangements are possible from the five letters MAMMM?
Five
How many different 5 letter arrangements can be formed from the letters in the name CATHY if each letter is used only once in each arrangement?
120
How many four-letter arrangements can be made of the letters a c e f and h if there is repetition of letters?
There are 5 letters: a c e f and h.If the letters can be repeated, then there are five possibilities for each space in the four-letter arrangement. The number of arrangements then is:5*5*5*5 = 54 = 625.
How many different arrangements of the letters in the word COLOR are there?
If you pick from each of the possible letters at each stage, then there are 5 possible options for the first letter. Then there are 4 possible options for the second. Then there are 3 possible options for the 3rd and so on. This leaves us with 5x4x3x2 = 120 different arrangements. However, each arrangement has been counted twice, as it doesn't matter which way around the Os go. So to get the true answer, we need to divide by 2. 120/2 = 60, and therefore the number of different arrangements of the letters in the word COLOR is 60.
How many 3 letter arrangements are possible from 26 letters if no letter can be repeated?
The number is 26*25*24 = 15600.
How many two letter arrangements can be made using the letters from PARK?
There are 12 two letter arrangements of the letters in PARK.
How many six letter arrangements are possible with a six letter word?
It depends on the letters and also on the words that have been placed on the board.
How many different four letter arrangements are there of the letters Tennessee?
There are 172 different arrangements.
How many ways can you arrange the letters PARTY if the first letter must be an A?
The number of arrangements of the letters PARTY, if the first letter must be an A is the same as the number of arrangements of the letters PRTY, and that is 4 factorial, or 24.
How many arrangements in a 3 letter word?
the arrangements occur. if there are two of the same letter then 12 all different letters then 24 three letters the same then 5 four letters the same then 1
What is the total number of different four-letter arrangements that can be formed from the letters in the word vertical if each letter is used only once in an arrangement?
You have eight letters to work with, and can use any four of them, but only once per combination. That means that the total number of possible combinations you can make is: 8! / (8 - 4)! = 8! / 4! = 8 * 7 * 6 * 5 = 1680 So there are 1680 possible combinations.
How many different arrangement can be made by taking 4 letter of the word ENGLISH?
Answer: 7P4 = 840 arrangementsNumber of letters in the word ENGLISH : 7Number of letters to take: 4Number of arrangements:= 7P4= 7!/(7-4)!= 5040/6= 840
