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How many bits of binary code do you need to represent the answer to the sum 10 6?
If you mean 10 + 6 that's 16 which is 10000 in binary
How does BCD differ from the straight binary number system?
To consider the difference between straight binary and BCD, the binary numbers need to be split up into 4 binary digits (bits) starting from the units. In 4 bits there are 16 possible values from 0000 to 1111 (0 to 15). In straight binary all of these possible combinations are used, thus: 4 bits can represent the decimal numbers 0-15 8 bits can represent the decimal numbers 0-255 12 bits can represent the decimal numbers 0-4095 16 bits can represent the decimal numbers 0-65535 etc In arithmetic, all combinations of bits are used, thus: 0000 1001 + 0001 = 0000 1010 In BCD or Binary Coded Decimal, only the representations of the decimal numbers 0-9 are used (that is 0000 to 1001 in binary), and the 4-bits (nybbles) are read as decimal digits, thus: 4 bits can represent the decimal digits 0-9 8 bits can represent the decimal digits 0-99 12 bits can represent the decimal digits 0-999 16 bits can represent the decimal digits 0-9999 In arithmetic, only the representations of decimal numbers are used, thus: 0000 1001 + 0001 = 0001 0000 When BCD is used each half of a byte is read directly as a decimal digit. BCD is obviously inefficient as storage (for large numbers) as each nybble is only holding 3/8 of the possible numbers, however, it is sometimes easier and quicker to work with decimal digits (for example when there is lots of display of counting numbers to do there is less binary to decimal conversion needing to be done).
What is the minimum number of bits required to represent 18427 in two's complement?
18427(10) = 1000111111111011(2)So, it will need 16 bits (16 digits from the binary value) for 18427 itself. For the complement (the sign), add 1 more bit: the answer is 17.
How may bits are needed to represent the decimal number 200?
log2 200 = ln 200 ÷ ln 2 = 7.6... → need 8 bits. If a signed number is being stored, then 9 bits would be needed as one would be needed to indicate the sign of the number.
How many bits are required to sample an incoming signal 4000 times per second using 64 different amplitude levels?
You will need many discrete bits. The number goes up because of the high number of amplitude levels.
How many bits need to represent the decimal number 200?
8
How many bits are need to represent colors?
Most modern digital cameras use 24 bits (8 bits per primary) to represent a color. But more or less can be used, depending on the quality desired. Many early computer graphics cards used only 4 bits to represent a color.
How many bits would be needed to represent a 45 character set?
45 in binary is 101101, so you need at least 6 bits to represent 45 characters.
What is the minimum number of bits would you need to represent 9 different values?
4.1 bit for 2,2 bits for 4,3 bits for 8,4 bits for 16.
How many bits of binary code do you need to represent the answer to the sum 10 6?
If you mean 10 + 6 that's 16 which is 10000 in binary
How many bits are required to represent the phrase recommended setting?
"recommended setting" There are 19 characters including the space between the two words. If the old convention of using 1 byte to represent a character, then we would need (19 x 8) which is 152 bits. If we use unicode as most modern computers use (to accommodate all the languages in the world) then 2 bytes will represent each character and so the number of bits would be 304.
How many bits are required to represent hexadecimal number ABE?
You need four bits for each hex digit since 4 bits can support a value from 0-15. Binary_____Hexidecimal 0_________0 1_________1 10________2 11________3 100_______4 101_______5 110_______6 111_______7 1000______8 1001______9 1010______A 1011______B 1100______C 1101______D 1111______F
How many bits you need to represent an alphabet letter?
Bit -- Value 1 -- 1 11 -- 3 111 -- 7 1111 -- 15 11111 -- 31 111111 -- 63 1111111 -- 127 11111111 -- 255 111111111-- 511 1111111111 -- 1023 Therefore - 10 bits would be more than adequate (unless you had to represent capitals and lower case - in which case you would need one more bit).
How many bits of address bus are required to address 1mb memory?
You need 20 bits of address bus to address 1 Mb of memory.
How many months do you need in the National Guard to get out?
96 months.
How many bits do you need to encode any signed integer between -1000 and 1000?
11 bits (which actually allows -1024 to 1023)
How does BCD differ from the straight binary number system?
To consider the difference between straight binary and BCD, the binary numbers need to be split up into 4 binary digits (bits) starting from the units. In 4 bits there are 16 possible values from 0000 to 1111 (0 to 15). In straight binary all of these possible combinations are used, thus: 4 bits can represent the decimal numbers 0-15 8 bits can represent the decimal numbers 0-255 12 bits can represent the decimal numbers 0-4095 16 bits can represent the decimal numbers 0-65535 etc In arithmetic, all combinations of bits are used, thus: 0000 1001 + 0001 = 0000 1010 In BCD or Binary Coded Decimal, only the representations of the decimal numbers 0-9 are used (that is 0000 to 1001 in binary), and the 4-bits (nybbles) are read as decimal digits, thus: 4 bits can represent the decimal digits 0-9 8 bits can represent the decimal digits 0-99 12 bits can represent the decimal digits 0-999 16 bits can represent the decimal digits 0-9999 In arithmetic, only the representations of decimal numbers are used, thus: 0000 1001 + 0001 = 0001 0000 When BCD is used each half of a byte is read directly as a decimal digit. BCD is obviously inefficient as storage (for large numbers) as each nybble is only holding 3/8 of the possible numbers, however, it is sometimes easier and quicker to work with decimal digits (for example when there is lots of display of counting numbers to do there is less binary to decimal conversion needing to be done).
