Study guides

☆☆

Q: How many bits do you need to represent months of the year?

Write your answer...

Submit

Still have questions?

Related questions

8

Most modern digital cameras use 24 bits (8 bits per primary) to represent a color. But more or less can be used, depending on the quality desired. Many early computer graphics cards used only 4 bits to represent a color.

45 in binary is 101101, so you need at least 6 bits to represent 45 characters.

If you mean "64 different characters", you need log2(64) = 6 different bits.

4.1 bit for 2,2 bits for 4,3 bits for 8,4 bits for 16.

If you mean 10 + 6 that's 16 which is 10000 in binary

36 bits

"recommended setting" There are 19 characters including the space between the two words. If the old convention of using 1 byte to represent a character, then we would need (19 x 8) which is 152 bits. If we use unicode as most modern computers use (to accommodate all the languages in the world) then 2 bytes will represent each character and so the number of bits would be 304.

You need four bits for each hex digit since 4 bits can support a value from 0-15. Binary_____Hexidecimal 0_________0 1_________1 10________2 11________3 100_______4 101_______5 110_______6 111_______7 1000______8 1001______9 1010______A 1011______B 1100______C 1101______D 1111______F

Bit -- Value 1 -- 1 11 -- 3 111 -- 7 1111 -- 15 11111 -- 31 111111 -- 63 1111111 -- 127 11111111 -- 255 111111111-- 511 1111111111 -- 1023 Therefore - 10 bits would be more than adequate (unless you had to represent capitals and lower case - in which case you would need one more bit).

96 months.

8

People also asked