You need four bits for each hex digit since 4 bits can support a value from 0-15.
Binary_____Hexidecimal
0_________0
1_________1
10________2
11________3
100_______4
101_______5
110_______6
111_______7
1000______8
1001______9
1010______A
1011______B
1100______C
1101______D
1111______F
To store the hexadecimal number FF, we need to convert it to binary first. FF in hexadecimal is equivalent to 1111 1111 in binary, which requires 8 bits to represent. Each hexadecimal digit corresponds to 4 bits in binary, so two hexadecimal digits (FF) require 8 bits to store.
Eight.
9 bits
FA2B = 2 bytes = 4 nibbles = 16 bits 1 1 1 1 . 1 0 1 0 . . . 0 0 1 0 . 1 0 1 1
8
To represent an eight-digit decimal number in Binary-Coded Decimal (BCD), each decimal digit is encoded using 4 bits. Since there are 8 digits in the number, the total number of bits required is 8 digits × 4 bits/digit = 32 bits. Therefore, 32 bits are needed to represent an eight-digit decimal number in BCD.
103
17 bits would allow a value up to 131071.
4 bits equal to half byte.8 bits is one byte.when converting hexadecimal digits to binary, each hexadecimal digits will take 4 binary digits, which means 4 bits.Because one binary digit means one bit having two values [true/false] or [on/off] like that.. [0/1]we can represent one hexadecimal digit as 4 bits like..for [7] as hexadecimal, we can say [0111] in bits.
Convert each group of 4 bits into one hexadecimal digit. 1010 is "A" in hexadecimal, so this particular number is "AA".
Count them: 643(10)=1010000011(2)
Binary: 1 bit Octal: 3 bits Hexadecimal: 4 bits Decimal: somewhere between 3 and 4 bits. In theory, about 3.32 bits.