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You need four bits for each hex digit since 4 bits can support a value from 0-15.

Binary_____Hexidecimal

0_________0

1_________1

10________2

11________3

100_______4

101_______5

110_______6

111_______7

1000______8

1001______9

1010______A

1011______B

1100______C

1101______D

1111______F

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Q: How many bits are required to represent hexadecimal number ABE?
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Related questions

The minimum number of bits required to store the hexadecimal number FF is?

To store the hexadecimal number FF, we need to convert it to binary first. FF in hexadecimal is equivalent to 1111 1111 in binary, which requires 8 bits to represent. Each hexadecimal digit corresponds to 4 bits in binary, so two hexadecimal digits (FF) require 8 bits to store.


What is The minimum number of bits required to store the hexadecimal number FF?

Eight.


What is the minimum number of bits required to represent the decimal 1000?

9 bits


How many bits are required to represent the hexadecimal number FA2B?

FA2B = 2 bytes = 4 nibbles = 16 bits 1 1 1 1 . 1 0 1 0 . . . 0 0 1 0 . 1 0 1 1


What is the minimum number if binary bits required to represent the decimal number 250?

8


How many bits are required to represent 32 digit decimal number?

103


What is the minimum number of bits required to represent the following decimal number 101000?

17 bits would allow a value up to 131071.


4 bits equal what?

4 bits equal to half byte.8 bits is one byte.when converting hexadecimal digits to binary, each hexadecimal digits will take 4 binary digits, which means 4 bits.Because one binary digit means one bit having two values [true/false] or [on/off] like that.. [0/1]we can represent one hexadecimal digit as 4 bits like..for [7] as hexadecimal, we can say [0111] in bits.


How do you convert the binary number 10101010 into hex?

Convert each group of 4 bits into one hexadecimal digit. 1010 is "A" in hexadecimal, so this particular number is "AA".


How many binary bits are required to represent the decimal number 643?

Count them: 643(10)=1010000011(2)


What is the no of bits that can be expressed in binaryoctaldecimal and hexadecimal system?

Binary: 1 bit Octal: 3 bits Hexadecimal: 4 bits Decimal: somewhere between 3 and 4 bits. In theory, about 3.32 bits.


Can two hexadecimal digits be stored in one byte?

Yes, a byte is 8 bits, and a one hexadecimal digit takes up four bits, so two hexadecimal digits can be stored in a byte. The largest hexadecimal digit is F (which is 15 in base ten.) In base two, this converts to 1111, which takes up four bits, which is why it only takes four bits to store a hexadecimal digit. With 8 bits, two hexadecimal digits can be stored (FF would be 11111111, which is 8 bits), and 8 bits make up a byte. Generally, 4 bits are always used to store a hexadecimal digit, using leading zeros where necessary. For example, the hexadecimal digit 5 would be stored as 0101, and the hexadecimal digits 5A would be stored as 01011010.