The answer is 49C6 = 49*48*47*46*45*44/(6*5*4*3*2*1) = 13,983,816
There are 15180 combinations.
Using the formula n!/r!(n-r)! where n is the number of possible numbers and r is the number of numbers chosen, there are 13983816 combinations of six numbers between 1 and 49 inclusive.
There are 49 3-digit numbers - from 108 to 990 inclusive.
49
nCr = n!/((n-r)!r!) → 49C8 = 49!/((49-8)!8!) = 49!/(41!8!) = 450,978,066 combinations.
49 - 17, D16
No. There are nearly 14 million combinations of 49 things taken 6 at a time. Excel does not have that many rows or columns to support that.
49
To determine how many times the digit 7 appears in the number 49, we need to break down the number into its individual digits. In this case, 49 has two digits: 4 and 9. Since there is no 7 in either of these digits, the number 49 does not contain the digit 7. Therefore, there are zero instances of the digit 7 in the number 49.
if we do not want to use the same number more than once then the answer is: 49*48*47*46*45*44 however if we can use a number more than once the solution is: 49^6
The number of combinations is 50C6 = 50*49*48*47*46*45/(6*5*4*3*2*1) = 15,890,700
49