The number of combinations is 50C6 = 50*49*48*47*46*45/(6*5*4*3*2*1) = 15,890,700
14 * * * * * Wrong! There are 15. 4 combinations of 1 number, 6 combinations of 2 number, 4 combinations of 3 numbers, and 1 combination of 4 numbers.
you could make a probability tree if you could be bothered
35
9000
To find the number of different combinations of the numbers 1 to 10, we can consider the combinations of choosing any subset of these numbers. The total number of combinations for a set of ( n ) elements is given by ( 2^n ) (including the empty set). For the numbers 1 to 10, ( n = 10 ), so the total number of combinations is ( 2^{10} = 1024 ). This includes all subsets, from the empty set to the full set of numbers.
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
14 * * * * * Wrong! There are 15. 4 combinations of 1 number, 6 combinations of 2 number, 4 combinations of 3 numbers, and 1 combination of 4 numbers.
Only one.
Assuming that the six numbers are different, the answer is 15.
you could make a probability tree if you could be bothered
35
9000
The rearrangement of 5 figure numbers will be 5x4x3x2x1 which is 120 combinations, when you don't repeat a number.
None. You do not have enough numbers to make even one combination.
To calculate the number of combinations with three numbers, you would use the formula for combinations, which is nCr = n! / r!(n-r)!. In this case, n is the total number of numbers you have to choose from, and r is the number of numbers you are choosing. So, if you have three numbers to choose from, there would be 3C3 = 3! / 3!(3-3)! = 6 / (6*0!) = 6 / 6 = 1 combination.
7
Using the combination fuction, chose three numbers from 45 numbers. The answer is 14,190.