There are: 10C7 = 120
-5
The answer is 7C5 = 21.
To determine the number of different two-person committees that can be formed from a group of six people, we use the combination formula ( C(n, k) = \frac{n!}{k!(n-k)!} ), where ( n ) is the total number of people and ( k ) is the number of people to choose. Here, ( n = 6 ) and ( k = 2 ). Thus, the number of combinations is ( C(6, 2) = \frac{6!}{2!(6-2)!} = \frac{6 \times 5}{2 \times 1} = 15 ). Therefore, 15 different two-person committees can be formed.
(9 x 8 x 7 x 6)/(4 x 3 x 2 x 1) = 126committees.
There are: 10C7 = 120
There are 2300 possible combinations.
They can't be split evenly into groups of six. Sixteen people can split into two groups of six, and there will be four people left over.
72
-5
-5
The answer is 7C5 = 21.
(9 x 8 x 7 x 6)/(4 x 3 x 2 x 1) = 126committees.
it has 20 people in the standing committee not how many people how many committees
1316
There are 16C6 = 16*15*14*13*12*11/(6*5*4*3*2*1) possible committees. That is, 8,008 of them.
120