72
There are 4845 ways to choose 4 people out of 20 20 choose 4 = 20! / (4!16!)
-5
The number of distinct, different 4-person committees that can be formedfrom a group of 32 people is(32!/28!) / (4!) = (32 x 31 x 30 x 29) / (4 x 3 x 2 x 1) = 35,960(but obviously, no more than four at a time.)
Possibilities are (9 x 8)/2 times (49 x 48 x 47 x 46)/24 = 366,121,728/48 =7,627,536 different committees.
120
There are: 10C7 = 120
They can't be split evenly into groups of six. Sixteen people can split into two groups of six, and there will be four people left over.
72
There are 4845 ways to choose 4 people out of 20 20 choose 4 = 20! / (4!16!)
There are 2300 possible combinations.
-5
it has 20 people in the standing committee not how many people how many committees
(9 x 8 x 7 x 6)/(4 x 3 x 2 x 1) = 126committees.
Eight. If you can't multiply by fives, then your either an idiot, or too young to be using the Internet.
-5
There are 10560 possible committees.