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There are 16C6 = 16*15*14*13*12*11/(6*5*4*3*2*1) possible committees.

That is, 8,008 of them.

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13y ago

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Related Questions

How many 3-person committees can be formed in a club of 8 members?

120


How many committees of 7 can be formed from a group of 10 people?

There are: 10C7 = 120


How many 6 person committees can be formed from a group of 16?

They can't be split evenly into groups of six. Sixteen people can split into two groups of six, and there will be four people left over.


How many different two person committees can be formed from a group of six people?

To determine the number of different two-person committees that can be formed from a group of six people, we use the combination formula ( C(n, k) = \frac{n!}{k!(n-k)!} ), where ( n ) is the total number of people and ( k ) is the number of people to choose. Here, ( n = 6 ) and ( k = 2 ). Thus, the number of combinations is ( C(6, 2) = \frac{6!}{2!(6-2)!} = \frac{6 \times 5}{2 \times 1} = 15 ). Therefore, 15 different two-person committees can be formed.


How many two person committees can be chosen from a group of nine people?

72


How many combinations of 4 person committees can be formed in a class of 20 students?

There are 4845 ways to choose 4 people out of 20 20 choose 4 = 20! / (4!16!)


How many 4-person committees are possible from a group of 9 people if there are no restrictions?

-5


How many different three member committees can be formed from a group of twenty-five people?

There are 2300 possible combinations.


How many committees does the house of reps have?

it has 20 people in the standing committee not how many people how many committees


How many 5 person committees can be selected from nine people?

To determine how many 5-person committees can be formed from nine people, you can use the combination formula ( C(n, k) = \frac{n!}{k!(n-k)!} ), where ( n ) is the total number of people, and ( k ) is the number of people to choose. In this case, ( n = 9 ) and ( k = 5 ). Thus, the number of ways to select the committee is ( C(9, 5) = \frac{9!}{5!(9-5)!} = \frac{9!}{5!4!} = 126 ). Therefore, there are 126 different 5-person committees possible.


How many different four person committees can be formed from a group of 9 people?

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How many committees of 5 people can be formed by a group of 40 people?

Eight. If you can't multiply by fives, then your either an idiot, or too young to be using the Internet.