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I presume you mean:

What is the size of each interior angle of a regular polygon if their total is 3600o?

The answer to this is 1637/11o ~= 163.6o.

The total of the interior angles of a polygon is

total = 180o x (number_of_sides - 2)

⇒ number_of_sides = (total ÷ 180o) + 2

⇒ number_of_sides = (3600o ÷ 180o) + 2

⇒ number_of_sides = 22

total = interior_angle x number_of_sides

⇒ interior_angle = total ÷ number_of_sides

⇒ interior_angle = 3600o ÷ 22

⇒ interior_angle = 1637/11o ~= 163.6o

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14y ago

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