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How many degrees in each interior angle does a polygon have if its equals 3600?
Wiki User
∙ 13y ago
I presume you mean:
What is the size of each interior angle of a regular polygon if their total is 3600o?
The answer to this is 1637/11o ~= 163.6o.
The total of the interior angles of a polygon is
total = 180o x (number_of_sides - 2)
⇒ number_of_sides = (total ÷ 180o) + 2
⇒ number_of_sides = (3600o ÷ 180o) + 2
⇒ number_of_sides = 22
total = interior_angle x number_of_sides
⇒ interior_angle = total ÷ number_of_sides
⇒ interior_angle = 3600o ÷ 22
⇒ interior_angle = 1637/11o ~= 163.6o
Wiki User
∙ 13y ago
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