I presume you mean:
What is the size of each interior angle of a regular polygon if their total is 3600o?
The answer to this is 1637/11o ~= 163.6o.
The total of the interior angles of a polygon is
total = 180o x (number_of_sides - 2)
⇒ number_of_sides = (total ÷ 180o) + 2
⇒ number_of_sides = (3600o ÷ 180o) + 2
⇒ number_of_sides = 22
total = interior_angle x number_of_sides
⇒ interior_angle = total ÷ number_of_sides
⇒ interior_angle = 3600o ÷ 22
⇒ interior_angle = 1637/11o ~= 163.6o
2280 :S
If it is a regular polygon with each interior angle of 120 degrees then it is an hexagon which will have 0.5((6^2)-3*6) equals 9 diagonals
A polygon cannot have an interior angle of 900 degrees because the sum of the interior angles of a polygon is calculated based on the number of its sides. For any polygon, each interior angle must be less than 180 degrees. Therefore, a single interior angle of 900 degrees is not feasible in Euclidean geometry.
The sum of the interior angles of any regular polygon of n sides is equal to 180(n - 2) degrees.
A polygon cannot have an interior angle of 8100 degrees, as the maximum interior angle for any polygon is less than 180 degrees. The sum of the interior angles of a polygon increases with the number of sides, but no individual angle can exceed 180 degrees in a convex polygon. If an angle were to be 8100 degrees, it would suggest a complex structure or a non-standard definition of a polygon. In standard geometry, such an angle would be impossible.
Im stuck on that too :/
120
No regular polygon can have an interior angle of 180 degrees or more. No regular polygon can have an interior angle of 180 degrees or more. No regular polygon can have an interior angle of 180 degrees or more. No regular polygon can have an interior angle of 180 degrees or more.
Any polygon can have an interior angle of 144 degrees. The measurement of an interior angle of a decagon is 144 degrees.
2280 :S
A Pentagon has an interior angle of 108 degrees.
If it is a regular polygon with each interior angle of 120 degrees then it is an hexagon which will have 0.5((6^2)-3*6) equals 9 diagonals
A polygon cannot have an interior angle of 900 degrees because the sum of the interior angles of a polygon is calculated based on the number of its sides. For any polygon, each interior angle must be less than 180 degrees. Therefore, a single interior angle of 900 degrees is not feasible in Euclidean geometry.
The sum of the interior angles of any regular polygon of n sides is equal to 180(n - 2) degrees.
A polygon cannot have an interior angle of 8100 degrees, as the maximum interior angle for any polygon is less than 180 degrees. The sum of the interior angles of a polygon increases with the number of sides, but no individual angle can exceed 180 degrees in a convex polygon. If an angle were to be 8100 degrees, it would suggest a complex structure or a non-standard definition of a polygon. In standard geometry, such an angle would be impossible.
The interior angles of a 15 sided polygon add up to 2340 degrees and if it is a regular polygon then each interior angle is 156 degrees.
an equilateral triangle, or equiangular triangle