28
4...
20.
(8*15)-16=104 diagonals in a 16 sided polygon.
20 diagonals in Octagan. For n-sided polygon, no of diagonals = (n choose 2 ) - n = 8C2 - 8 = 28 - 8 = 20
8+7+6+5+4+3+2+1 = 36 diagonals
20 diagonals For any n-sided polygon, the formula for the number of diagonals is (n/2) x (n-3), so for an octagon it is (8/2) x (8-3) = 4 x 5 = 20.
An eight-sided polygon has 8 vertices. Consider1st vertex = 7 diagonals to other vertices2nd vertex = 6 diagonals to other vertices (since one has now been used)3rd vertex = 54th vertex = 45th vertex = 36th vertex = 27th vertex = 18th vertex = 0, so7+6+5+4+3+2+1 = 28Improved Answer:-Formula for finding diagonals of a polygon 0.5*(n2-3n) when n is the number of sides0.5*(82-24) = 20 diagonals
8
Yes, an octogon is a 8 sided polygon
An 8 sided octagon has 20 diagonals according to the formula 0.5*(n^2 -3n) whereas n is the number of sides of the polygon.
An 8-sided polygon is called an octagon.
Yes; a 8 sided figure is a polygon.