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An eight-sided polygon has 8 vertices. Consider

1st vertex = 7 diagonals to other vertices

2nd vertex = 6 diagonals to other vertices (since one has now been used)

3rd vertex = 5

4th vertex = 4

5th vertex = 3

6th vertex = 2

7th vertex = 1

8th vertex = 0, so

7+6+5+4+3+2+1 = 28

Improved Answer:-

Formula for finding diagonals of a polygon 0.5*(n2-3n) when n is the number of sides

0.5*(82-24) = 20 diagonals

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13y ago

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