20.
infiniteImproved Answer:-The formula is: 0.5*(n2-3n) where n is the number of sides of the polygonSo: 0.5*(144-36) = 54 diagonals
In a polygon with n sides, we have n(n-3)/2 diagonals. In a convex polygon with n sides, you can draw n-3 diagonals from each vertex, but you are counting each one twice you so you need to divide by do. That is why we have n(n-3) divided by 2
In a polygon with n sides, the number of diagonals that can be drawn from one vertex is given by the formula (n-3). Therefore, in a 35-sided polygon, you can draw (35-3) = 32 diagonals from one vertex.
You cannot draw a diagonal from a vertex to itself. So that is 1. Also, the diagonals to the adjacent vertices on either side will actually be the sides of the polygon, not diagonals. Those are the other 2.
it should make a square leaned over
It depends if the polygon is convex or concave but if it is a regular polygon it would have 560
153 diagonals.
what is a regular polygon
infiniteImproved Answer:-The formula is: 0.5*(n2-3n) where n is the number of sides of the polygonSo: 0.5*(144-36) = 54 diagonals
A 5-sided polygon is called a pentagon. You can draw up to 5 diagonals in a pentagon.
n-3 diagonals. Of the n vertices of the polygon, you cannot draw diagonals to the two adjacent vertices since these are sides of the polygon and so not diagonals. And you cannot draw a diagonal from a vertex to itself. So those are three vertices that are ruled out, leaving n-3.
Only one.
21
it is impossible
In a regular polygon with ( n ) sides, the number of non-intersecting diagonals that can be drawn is given by the formula ( \frac{n(n-3)}{2} ). However, if you are looking for the number of ways to draw non-intersecting diagonals that divide the polygon into triangles (triangulation), the count is represented by the ( (n-2) )-th Catalan number, which is ( C_{n-2} = \frac{1}{n-1} \binom{2(n-2)}{n-2} ). Thus, the interpretation of "non-intersecting diagonals" can vary based on context.
In a polygon with n sides, we have n(n-3)/2 diagonals. In a convex polygon with n sides, you can draw n-3 diagonals from each vertex, but you are counting each one twice you so you need to divide by do. That is why we have n(n-3) divided by 2
In a polygon with n sides, the number of diagonals that can be drawn from one vertex is given by the formula (n-3). Therefore, in a 35-sided polygon, you can draw (35-3) = 32 diagonals from one vertex.