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The 5 can appear in any of the 4 positions, and for each of those 4 positions the other 3 positions can be filled by any of the other eight digits (1-4, 6-9).

→ 4 x 8 x 8 x 8 = 2048 different numbers with the 5 appearing exactly once.

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Q: How many different four digits number can be formed can be formed using digits 1 2 3 4 5 6 7 8 9 such that digit 5 appears exactly once?
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