answersLogoWhite

0


Best Answer

7*7 = 49 numbers.

7*7 = 49 numbers.

7*7 = 49 numbers.

7*7 = 49 numbers.

User Avatar

Wiki User

โˆ™ 2013-03-30 19:45:05
This answer is:
๐Ÿฆƒ
0
๐Ÿคจ
0
๐Ÿ˜ฎ
0
User Avatar
Study guides

Algebra

20 cards

A polynomial of degree zero is a constant term

The grouping method of factoring can still be used when only some of the terms share a common factor A True B False

The sum or difference of p and q is the of the x-term in the trinomial

A number a power of a variable or a product of the two is a monomial while a polynomial is the of monomials

โžก๏ธ
See all cards

J's study guide

1 card

What is the name of Steve on minecraft's name

โžก๏ธ
See all cards

Steel Tip Darts Out Chart

96 cards

170

169

168

167

โžก๏ธ
See all cards
More answers
User Avatar

Wiki User

โˆ™ 2013-03-30 19:45:05

7*7 = 49 numbers.

User Avatar

Add your answer:

Earn +20 pts
Q: How many different two digit numbers can you form using the digits 1 2 3 5 6 7 and 9 with repetition?
Write your answer...
Submit
Related questions

How many two digit numbers can you form using the digits 1235679 with repetition allowed?

You have seven different digits (symbols) to choose from, so you can form seven different one digit numbers and 7×7=72=49 different two digit numbers.


Where d represents a digit from 0 9 how many different ISBN numbers are possible if repetition of digits is allowed?

There are 10 to the 10th power possibilities of ISBN numbers if d represents a digit from 0 to 9 and repetition of digits are allowed. That means there are 10,000,000,000 ISBN numbers possible.


How many three digit numbers can be formed using the digits 873 and 6 without repetition?

I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24


How many 3 digit number can be made using the digits 2 4 7 9?

24 three digit numbers if repetition of digits is not allowed. 4P3 = 24.If repetition of digits is allowed then we have:For 3 repetitions, 4 three digit numbers.For 2 repetitions, 36 three digit numbers.So we have a total of 64 three digit numbers if repetition of digits is allowed.


How many 2-digit numbers can be produce using the digits 123456789 if repetition is not allowed?

-123456787


How many 3 digit numbers are possible from the digits 012345?

Assuming that the first digit can't be zero: If repetition of digits is permitted: (5 x 6 x 6) = 180 numbers of 3 digits. If repetition of digits is not permitted: (5 x 5 x 4) = 100 numbers of 3 digits.


How many 4-digit numbers are possible if the hundreds digit is 8 and if repetition of digits is allowed?

-4


How many different two digit numbers can you form using the digits 1 2 5 7 8 and 9 with repetition?

30 without repetition (6P2) 66 with repetition (12C2)


How many different 3 digit number can be formed from 13579 if there's repetition?

As there are 5 different digits, allowing for repetition of a digit, the first digit can be any of the 5, and for each of these, the second can be any of the 5, and so for the third, making: 5 x 5 x 5 = 125 different 3-digit numbers.


How many different two digit numbers can be formed using the digits 2 3 5 6 8?

20 of them, if repetition is not allowed.


How many 4 digit numbers can be made to give the sum of 6?

If repetition of digits is allowed, then 56 can.If repetition of digits is not allowed, then only 18 can.


How many 3 digit numbers can be formed from the digits 1234?

64 if repetition is allowed.24 if repetition is not allowed.


How many 13 digit numbers are possible by using the digits 12345 which are divisible by 4 if repetition of digits is not allowed?

If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.


How many different three digit numbers can you form using the digits 1 2 3 5 6 7 and 9 without repetition?

There are seven possible digits for the first digit and 6 digits for the second (minus one digit for the digit used as the first digit) and 5 options for the last digit (minus one again for the second digit) and then you just multiply them all together to get a total possible combination of 210 numbers that are possible.


How many possible 3 digit numbers can be made using the digits 604?

There are 4 possible numbers if the digits are not repeated; 18 if they are. Those are 3-digit numbers, assuming that zero would not be a leading digit. If zero is allowed for a leading digit, then you can have 6 for the non repeated, and 27 if repetition.


How many different 2 digit numbers can you form using the digits 1 2 3 5 6 7 and 9 with repetition allowed?

10


How many 3-digit numbers using the digits 0-7 are possible if repetition are allowed?

290


How many 4 digit numbers can be formed from digits 123456789?

5040 different 4 digit numbers can be formed with the digits 123456789. This is assuming that no digits are repeated with each combination.


How many different three digit numbers can be written using the digits 1 through 9?

You can select 9 numbers for the first digit, 8 numbers for the second digit, and 7numbers for the third digit; so 504 (e.g. 9*8*7) different three digit numbers can be written using the digits 1 through 9.


What 5 digit number has Numbers increasing from the left Each digit is different 1st and 5th digits are square numbers 1st and 4th digits are cubed numbers 2nd 3rd digits are even?

12689 14689 12489


How many 3 digit numbers can be formed using the digits 1 to 9 without repetition?

9*8*7 = 504 of them.


How many 3 digit numbers can be formed by the digits 4 5 9 without repetition?

3*2*1 = 6 of them.


What is the sum of all the four digit numbers formed using the digits 0 1 2 and 3 if repetition is allowed?

It is 415968.


How man 7 digit combinations can be made using numbers 0 through 9?

10^7 if the repetition of digits is allowed. 9*8*7*6*5*4*3 , if the repetition of digits is not allowed.


How many 2-digit numbers can be formed using the digits 1 3 7 if repetition of digits is allowed?

Possible solutions - using your rules are:- 11,13,17,31,33,37,71,73 &77