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How many 3 digit numbers can be formed using the digits 2 3 5 6 7 9 if repetition of digits is not allowed?
120 There are 6 digits in total. The numbers with 3 digits, with all digits distinct from each other, are the permutations of the 6 digits taken 3 at a time, and therefore there are 6*5*4 = 120 of them.
How many different two digit numbers can you form using the digits 1 2 5 7 8 and 9 with repetition?
30 without repetition (6P2) 66 with repetition (12C2)
How many different 2 digit odd numbers can be formed from the digits 1 through 8 if no digits are repeated in a number?
36
How many 3 digit number are formed using the digits 3 5 7?
With repeating digits, there are 33 = 27 possible combinations.Without repeating any digits, there are 6 combinations:357375537573735753
How many 8 digit numbers can be formed by the digits 1234567890?
u culd make 80
How many 3 digit numbers can be formed from the digits 1234?
64 if repetition is allowed.24 if repetition is not allowed.
How many 13 digit numbers are possible by using the digits 12345 which are divisible by 4 if repetition of digits is not allowed?
If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.
How many numbers can be formed using the digits 37 and 9 without repetition?
15 of them.
How many 3 digits odd numbers can be formed from the digits 1 2 3 4 and 5 if repetition is not allowed?
125
How many 5 digits can be formed using the digits 0 2 3 4 5 when repetition is allowed that the number formed is divisible by 2 and 5 or both?
There are 2000 such numbers.
How many 4 digit numbers can be formed from digits 123456789?
5040 different 4 digit numbers can be formed with the digits 123456789. This is assuming that no digits are repeated with each combination.
How many 3-digit numbers can be formed by the digits 4 5 9 without repetition?
Six (6)
How many three digit numbers can be formed using the digits 873 and 6 without repetition?
I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24
How many 2-digit numbers can be formed using the digits 1 3 7 if repetition of digits is allowed?
Possible solutions - using your rules are:- 11,13,17,31,33,37,71,73 &77
How many 5 digit number can be formed using the digits 02345when repetition is allowed such that the number formed is divisible by 2 or 5 or both?
There are 2000 such numbers.
How many 3 digit numbers can be formed using the digits 1 to 9 without repetition?
9*8*7 = 504 of them.
How many 3 digit numbers can be formed by the digits 4 5 9 without repetition?
3*2*1 = 6 of them.
