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One must first consider the number of ordered ways that 4 students may be chosen, and then divide that by the number of ways the four may have been ordered to create a number of distinct groups.

For the orders, there are 30 choices for the first, 29 for the second, 28 for the third, and 27 for the fourth. However, there are a 4 ways within the four to pick the first, 3 ways for the second, 2 for the third, and 1 left for the fourth. The answer may be expressed by the following:

30 x 29 x 28 x 27

______________

1 x 2 x 3 x 4

which evaluates to 27,405 committees.

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Q: How many different ways can 4 students be chosen to serve on a committee from a group of 30 students?
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How many different ways can 4 kids be chosen to serve on a committee from a group of 30 kids?

40 x 39 x 38 x 37 = 2193360


How many ways can a committee of 3 students be chosen from a total count of 1514 students?

The first member chosen can be any one of 1,514 students.The second member chosen can be any one of the remaining 1,513 students.The third member chosen can be any one of the remaining 1,512 students.So there are (1,514 x 1,513 x 1,512) ways to choose three students.But for every group of three, there are (3 x 2 x 1) = 6 different orders in which the same 3 can be chosen.So the number of `distinct, unique committees of 3 students is(1514 x 1513 x 1512) / 6 = 577,251,864


How many ways can a committee of three be chosen from a total amount of 4463 students?

The first member chosen can be any one of 4,463 students.The second member chosen can be any one of the remaining 4,462 students.The third member chosen can be any one of the remaining 4,461 students.So there are (4,463 x 4,462 x 4,461) ways to choose three students.But for every group of three, there are (3 x 2 x 1) = 6 different orders in which the same 3 can be chosen.So the number of `distinct, unique committees of 3 students is(4463 x 4462 x 4461) / 6 = 14,805,989,111


How many different 3 member teams can be formed from a group of 6 students?

18


How many ways can a committee of 2 teachers and 5 students to be formed from 7 teachers and 25 students?

For this type of problem, order doesn't matter in which you select the number of people out of the certain group. We use combination to solve the problem.Some notes to know what is going on with this problem:• You want to form a committee of 2 teachers and 5 students to be formed from 7 teachers and 25 students • Then, you select 2 teachers out of 7 without repetition and without considering about the orders of the teachers.• Similarly, you select 5 students out out 25 without repetition and without considering about the orders of the students.Therefore, the solution is (25 choose 5)(7 choose 2) ways, which is equivalent to 1115730 ways to form such committee!

Related questions

How many ways can a group of 3 students be chosen from a class of 30 students?

3 students can be chosen from a class of 30 in (30 x 29 x 28) = 24,360 ways.But each group of the same 3 students will be chosen in six different ways.The number of different groups of 3 is 24,360/6 = 4,060 .


How many way can a committee four b chosen from group of 6?

15


How many different ways can 4 kids be chosen to serve on a committee from a group of 30 kids?

40 x 39 x 38 x 37 = 2193360


How many ways can a committee of 3 students be chosen from a total count of 1514 students?

The first member chosen can be any one of 1,514 students.The second member chosen can be any one of the remaining 1,513 students.The third member chosen can be any one of the remaining 1,512 students.So there are (1,514 x 1,513 x 1,512) ways to choose three students.But for every group of three, there are (3 x 2 x 1) = 6 different orders in which the same 3 can be chosen.So the number of `distinct, unique committees of 3 students is(1514 x 1513 x 1512) / 6 = 577,251,864


How many ways can a committee of three be chosen from a total amount of 4463 students?

The first member chosen can be any one of 4,463 students.The second member chosen can be any one of the remaining 4,462 students.The third member chosen can be any one of the remaining 4,461 students.So there are (4,463 x 4,462 x 4,461) ways to choose three students.But for every group of three, there are (3 x 2 x 1) = 6 different orders in which the same 3 can be chosen.So the number of `distinct, unique committees of 3 students is(4463 x 4462 x 4461) / 6 = 14,805,989,111


If a committee consists of 7 women and 4 men if a member of the committee is chosen at random to act as chairperson what is the probability that the choice is a woman?

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A committee consists of 7 women and 4 men if a member of the committee is chosen at random to act as chairperson what is the probability that the choice is a woman?

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