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Unfortunately sugar is an imprecise term. It is better to specify glucose (usually means dextrose) or sucrose or fructose etc. A 5 percent solution of one of these sugars would contain 5 grams weight dissolved in 100mL of water (or could be another solvent).
A. 2 g
This is (mass of solute) divided by (mass of total solution) expressed as a percentage. The solute is what you are dissolving into the solution. Example: you have 90 grams of water, and you add 10 grams of salt (sodium chloride). The water is the solvent, sodium chloride is the solute, and the solution is salt water. 90 grams + 10 grams = 100 grams (mass of total solution). (10 grams) / (100 grams) = 0.1 --> 10% mass mass percent concentration.
Mass percent = grams of solute/total grams of solution Mole fraction = mols component/total mols mix. Molarity = mols solute/L solution Molality = mols solute/kg solvent Hope this helps :)
dextrose
8.0 g according to my teacher but i dont know the formula
23.75 mg of Dextrose is added by intravenous injection of 475 ml of this solution .. wrong!5% WV means 5 grams/100ml ; therefore 23.75 grams/475ml; since there's 1000mg/gramthe number of mg dextrose added by IV injection of 475ml = 23750mg !
50 grams
Unfortunately sugar is an imprecise term. It is better to specify glucose (usually means dextrose) or sucrose or fructose etc.A 5 percent solution of one of these sugars would contain 5 grams weight dissolved in 100mL of water (or could be another solvent).Read more: What_does_a_5_percent_sugar_solution_mean
Unfortunately sugar is an imprecise term. It is better to specify glucose (usually means dextrose) or sucrose or fructose etc. A 5 percent solution of one of these sugars would contain 5 grams weight dissolved in 100mL of water (or could be another solvent).
50 g
You have 100 grams of pure dextrose and 9 grams of pure sodium chloride added to one liter of distilled water. The solution is sterilized and packed in polypropylene or polyethylene bottles.
I hope you don't work in a hospital, and I also hope you have passed 7th grade.But, 5% of a 1 L (1000 g) solution would be 50 grams.
2g?
A. 2 g
40.8 grams
it has exactly 29.34098 grams of solute