Unfortunately sugar is an imprecise term. It is better to specify glucose (usually means dextrose) or sucrose or fructose etc.
A 5 percent solution of one of these sugars would contain 5 grams weight dissolved in 100mL of water (or could be another solvent).
Read more: What_does_a_5_percent_sugar_solution_mean
Double the amount of solvent.
2.5 is the answer....5(.04)+.10(x)= .06(5+x).2+.1x=.3+.06x.04x=.1or 4x=10 so x =2.5
12.5
first calculate vd * CD =Vc * Cc Vc=50 * 2 / 5 =20ml
approximalety 2.94 molar
Double the amount of solvent.
Unfortunately sugar is an imprecise term. It is better to specify glucose (usually means dextrose) or sucrose or fructose etc. A 5 percent solution of one of these sugars would contain 5 grams weight dissolved in 100mL of water (or could be another solvent).
If 3 litres has 10% solution of sugar, the sugar comprises 300ml (i.e. a tenth of 3000). If we want 300ml to be 5% then we need a total of 100/5 * 300 = 6,000ml (6 litres). So we need to add 3 more litres of water. In other words, to halve the percentage of sugar we need to double the total solution from 3 litres to 6 litres.
If it is made by weight, .5 % sucrose solution will be 5 g of sucrose (sugar) dissolved per 100 g of solvent (e.g. water)
Dextrose is a synonym of D-glucose (also known as grape sugar, corn sugar, and when it's present in blood, blood sugar). In 2013, Dextrose 5 percent in lactated Ringer's injection was recalled. This recall stemmed from allegations of the product having mold in it.
true
Take 100 grams of 5% solution and do one of the following:Mix 95 g of it with 5 grams of sugar to end up with 100 g of 10% solution, or, when you are short of sugar:Evaporate 50 grams of water from 100 g of the 5% solution to end up with 50 g of 10% solution.
get 5%
spend more on sugar
You dillute it with some more of the same solvent used for the 6 percent solution - pressumably water.
50liters
molarity of 5% NaCl solution would be 1.25M.