50 grams
The percent concentration is 13,75 %.
12.5
1 percent = 10 grams 2 % = 20 grams x 3 liters = 60 grams
If the percentages specified are by mass and the 900 ml of water are assumed to be at standard temperature and pressure, this problem can be solved as follows: The 900 ml of water will have a mass of 900 grams. Call the unknown mass of the 37 percent solution to be added m. this will contain 0.37m grams of formaldehyde and 0.63m grams of water, and 0.37m/(900 + m) = 0.10. Then, multiplying both sides by (m + 900), 0.37m = 0.10m + 90, or 0.27m = 90, or m = 3.3 X 102 grams of the 37 % solution to be added, to the justified number of significant digits.
This solution contain 26,3 g NaOH.
50 g
40.8 grams
it has exactly 29.34098 grams of solute
4.25 L of a 0.25 M solution of NaF contain 1,062 moles sodium fluoride.
The percent concentration is 13,75 %.
12.5
Need to know how much of the solution you have.
This is (mass of solute) divided by (mass of total solution) expressed as a percentage. The solute is what you are dissolving into the solution. Example: you have 90 grams of water, and you add 10 grams of salt (sodium chloride). The water is the solvent, sodium chloride is the solute, and the solution is salt water. 90 grams + 10 grams = 100 grams (mass of total solution). (10 grams) / (100 grams) = 0.1 --> 10% mass mass percent concentration.
The mass of sodium hypochlorite in 2,5 kg solution is 131,25 g.Sodium chloride is only the product of a decomposition.
See the two Related Questions to the left for the answer.The first is how to prepare a solution starting with a solid substance (and dissolving it). The second question is how to prepare a solution by diluting another solution.
The answer is 8 g NaCl.
32.4