12.5
50 grams
W-V percent concentration g/mL = 1.20g/240mL = 0.005 g/mL percent
The answer is zero. You have asked the question incorrectly.
222.223 ml @ 20% solution = 44.444 ml 277.777 ml @ 65% solution = 180.555 ml total = 225 ml out of 500 ml = 45%
4 ml
50 grams
64 (g) / 250 (mL) = 0.256 g/mL = 256 g/L
The water volume is 212,5 mL.
1% solution = 1 gram per 100 mL, 10 grams per liter 20 grams
Is the makeup of the solution expressed as "percent by mass"? If so, to calculate molarity (or normality), you have to also know the density of the solution Step 1. Lets say the solution is 14%, and the density is 1.09 g/mL. We can write the following: (14 grams solute/100 grams solution) (1.09 grams solution/ mL solution) Step 2. Multiplying and cancelling from step 1 gives you 15.26 grams solute / 100 mL solution. Multiplying top and bottom by 10 gives you 152.6 grams solute per liter. Step 3. Molarity is number of moles per liter. Divide the 152.6 grams of the solute by the forumua weight (or molecular weight) of the solute, and you have the number of moles of solute. This number is therefore the molarity of the solution. If the solution is "percent by volume", the number you have is number of grams per 100 mL. Multiply by 10, and you have grams per liter. Then divide by the formula weight, and you have the molarity.
600 mL of 0,9 % sodium chloride: 6 x 0,9 = 5,4 grams NaCl
Does not convert; milligrams (mg) and grams (g) are measures of weight or mass and mL (milliliters) is a measure of volume.
Approximately 250 ml, maybe just a bit less.
C7H5N3O6 Molarity = moles of solute/Liters of solution (250 ml = 0.25 Liters ) 0.100 M C7H5N3O6 = X moles/0.25 L = 0.025 moles -------------------------now, 0.025 moles C7H5N3O6 (227.14 grams/1 mole C7H5N3O6) = 5.68 grams TNT ====================a good firecracker!
25 mL
W-V percent concentration g/mL = 1.20g/240mL = 0.005 g/mL percent
The answer is zero. You have asked the question incorrectly.