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The question is the same as:

"After removing the 4 aces from a standard deck, how many different hands

of 9 cards can be dealt from the remaining 48 ?"

The calculation is

48! / (39! x 9!) = (48 x 47 x 46 x 45 x 44 x 43 x 42 x 41 x 40) / (9 x 8 x 7 x 6 x 5 x 4 x 3 x 2)

We get 1,677,106,640 .

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Q: How many hands of 13 cards containing all 4 aces can be dealt from a 52 cards?
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