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Use this formula.

q(in Joules) = Mass * specific heat * change in temperature

I will use specific heat of water at 25 C. You can look up specific heat of steam. You say " heat to " so I assume you have final and initial heat backwards.

q = 25.0 grams H2O * 4.180 J/gC * (100.0 C - 29.25 C )

q = 7393 Joules

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Q: How many joules of energy are needed to heat 25.0 grams of steam from 100.0 degrees Celsius to 29.25 degrees Celsius?
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