This question cannot be answered sensibly. A square foot is a measure of area, with dimensions [L2]. A metre is a measure of distance, with dimensions [L]. Basic dimensional analysis teaches that in most cases you cannot convert between measures with different dimensions without additional information.
You can't convert that. Those units measure different things.
The impact velocity of a rock thrown horizontal from a cliff depends on two things, the initial speed of the rock (vi) and the height of the cliff (h). The final velocity (impact velocity) is represented by vfFor this formula, air resistance is neglected, and acceleration due to gravity is assumed to be 9.8 m/s2. The acceleration is positive here because down is being treated as the positive direction. You will get the same result if you use negative 9.8 m/s2 and make the height negative. sqr() means square root.vf = sqr(19.6h + vi2)For example if the rock was thrown off a 3 meter high cliff at 20 m/s, the impact velocity would be sqr(19.6 x 3 + 202), which would be sqr(58.8 + 202), which would be 21.42 m/s.The angle relative to the ground is the inverse tangent of sqr(19.6h)/viwhich in this case is tan-1( sqr(19.6 x 3)/20), which is tan-1(7.67/20) which is 21.0 degrees.
Watts of Power are not 'drawn', it just exists, or is generated by electrical interaction in the circuit. Amperage is 'drawn' by a load. The equation you're looking for is: P = VI, so P = (10)(120) = 1200 Watts, or 1.2 kW. If you have a Three-Phase circuit, the eq changes to: P = VI(square root of 3). 1.73 is usually good enough to use as a value for the sqr 3.
A definitive answer cannot be given to that question. As the planets orbit the sun, their distances from each other are constantly changing. At their closest Jupiter and Saturn would be about 403,000,000 miles from each other.
Considering the rain droplets as spherical body. We have two forces acting on the rain drop when it is falling through the sky, namely the resistance force due to friction(drag force)upwards and its weight downwards. Th rain drop falling from such distance attain a terminal velocity while falling i.e their speed becomes constant after sometime. This happens when the drag force equals the weight of drop,, this happens because drag force increases with velocity of the drop. Drag force= .5*rho*v2*A(frontal area)*Cd(coefficient of drag) Weight=m*g=rho*volume of spherical drop=rho*4/3*r3. When we equalize it, we get the Terminal Velocity(v) varying directly as sqr of r(radius of drop) So larger drop means, larger terminal velocity and hence less time taken for falling. So larger rain drop falls faster.
1480
231 m2 is about 2,486.5 square feet.
You can't convert that.
Since there is 9 square feet per square yard, if you have 240 square yards, then you have: 9*240 = 2160 square feet.
392040 sqr ft
The sin of 30 is sqr(3)/2 so 6 * sqr(30) is 6 * sqr(3)/2 this is also 6/2 * sqr(3) which simplifies to 3 * sqr(3) which is approximately 5.19615242
1 shotangsho = 436 sqr feet (approx)
54 = 625 (to find out sqr rt 625 then sqr rt again)
Answer: 2125 m² = 22,873.309 square feet.
It is 2x2 - 7x + 9
42x39/10.76 = 152.230483 sqr m
x=5/2*sqr(3)