It is 2x2 - 7x + 9
54 = 625 (to find out sqr rt 625 then sqr rt again)
I'm asuming you meant "ten theta"the square of 5 is 2525 divided by 10 is 2.5so theta equals 2.5there you go =)
320 = 2x^2 + 12x 0 = 2x^2 +12x -320 Using the quadratic formula x = (-12 + sqr(144+4*2*320))/4 and x= (-12 - sqr(144+4*2*320))/4 x =( -12 + sqr(2560))/4 = 9.649 to 3 d.p. and x=(-12 - sqr(2560))/4 = -15.649 to 3 d.p
231 m2 is about 2,486.5 square feet.
sqr(-30) is i*sqr(30) We use i to represent the sqr(-1) because it is called an imaginary number. It takes an imagination to work with it. It is not fictitious.
The sin of 30 is sqr(3)/2 so 6 * sqr(30) is 6 * sqr(3)/2 this is also 6/2 * sqr(3) which simplifies to 3 * sqr(3) which is approximately 5.19615242
54 = 625 (to find out sqr rt 625 then sqr rt again)
You can't convert that.
I'm asuming you meant "ten theta"the square of 5 is 2525 divided by 10 is 2.5so theta equals 2.5there you go =)
x=5/2*sqr(3)
2x2-2x=12x2-2x-1=0a=2 b=-2 c=-1x= (-b +- sqr(b2-4ac))/2ax= (2 +- sqr(4 + 8))/4x= (2 +- sqr(12))/4x = 1/2 +- sqr(12)/4x ~= .5 +- 0.8660x ~=-0.3660 or x ~= 1.3660
320 = 2x^2 + 12x 0 = 2x^2 +12x -320 Using the quadratic formula x = (-12 + sqr(144+4*2*320))/4 and x= (-12 - sqr(144+4*2*320))/4 x =( -12 + sqr(2560))/4 = 9.649 to 3 d.p. and x=(-12 - sqr(2560))/4 = -15.649 to 3 d.p
231 m2 is about 2,486.5 square feet.
Area is not measured in centimeter units. It may be guessed that the question should have indicated the area in square centimeters.The area of a regular pentagon is given as:A = s * s * sqr(25 + 10*(sqr(5)) / 4Solve for s:s = 2 * sqr (A / sqr(25 + 10*(sqr(5)))Insert the area of 600 square centimters:s = 2 * sqr (600 cm*cm / sqr(25 + 10*(sqr(5)))s = aproximately 19.67 cm
sqr(-30) is i*sqr(30) We use i to represent the sqr(-1) because it is called an imaginary number. It takes an imagination to work with it. It is not fictitious.
x=81
110