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How many ml of 40 percent acid should be added to pure acid to make 75 ml of 65 percent acid?
Wiki User
∙ 12y ago
The total volume of the new acid solution is 75 mL, and this solution is 65%, so the amount of acid in this solution is (0.65)*75mL = 48.75 mL
You have two equations and two unknowns:
x + y = 75
(0.40)*x + (1)*y = 48.75 {0.40 represents 40% and 1 represents 100% pure}
Solve and get x = 43.75 and y = 31.25, so you need 43.75 mL of the 40% acid and 31.25 mL of the pure acid.
Wiki User
∙ 12y ago
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