0
How many number combinations are possible in a 6 number combination using 1-46 and using each number only once per combination?
Wiki User
∙ 11y ago
46 x 45 x 44 x 43 x 42 x 41 = 6,744,109,680
* * * * *
That is the number of permutations. The number of combinations - where the order of the number does not matter (eg in a lottery) - is
46*45*44*43*42*41/(6*5*4*3*2*1) = 9,366,819
Wiki User
∙ 11y ago
Add your answer:
Earn +20 pts
What are the 5-number combinations not using any number twice?
There are infinitely many numbers and so infinitely many possible combinations.
How many symbols can you make with a 7 LED grid?
In a 7 segment display, the symbols can be created using a selected number of segments where each segment is treated as a different element.When 1 segment is used, the possible positions are 7because it can be any of the 7 segments (7C1=7).When 2 segments are used, the number of possible combinations are 7C2=21.When 3 segments are used, the number of possible combinations are 7C3=35When 4 segments are used, the number of possible combinations are 7C4=35When 5 segments are used, the number of possible combinations are 7C5=21When 6 segments are used, the number of possible combinations are 7C6=7When 7 segments are used, the number of possible combinations are 7C7=1Adding the combinations, 7+21+35+21+7+1=127Therefore, 127 symbols can be made using a 7 segment display!
How many two digit number combinations can you get using the number 1234 without repeating a digit?
There are twelve possible solutions using the rule you stated.
How many 4 digit combinations are there in the number 6000 using only 6 and 0?
There is only 1 combination.
What are the 100000 number combinations you can make using 0 - 9?
The question is incorrect since there are 210 - 1 possible combinations. The digit 0 can be in the combination or out. That gives 2 ways. With each, the digit 1 can be in the combination or out - 2*2 = 22 ways. With each, the digit 2 can be in the combination or out = 23 ways. With each, the digit 3 can be in the combination or out = 24 ways. etc. So 210 ways in all except that one of them is the null combination. Now 210 = 1024 so there are only 1023 combinations. If, instead, you allow the digits to be used many times, there is no limit to the number of combinations.
What is the number of possible combinations using 7 digits?
128
What are the 5-number combinations not using any number twice?
There are infinitely many numbers and so infinitely many possible combinations.
What possible combinations using 4 character A-Z?
140 possible combinations
How many combinations are there for a 6 digit number using the numbers 0 to 9?
If you can repeat the numbers within the combination there are 10,000 different combinations. If you cannot repeat the numbers within the combination, there are 5040 different combinations.
How many 4 number combinations are their using numbers 1469?
There is only one combination. The order does not matter in a combination.
How many possible 4 digit combinations are there using 0-9. how many different combination codes are possible?
There are 210 4 digit combinations and 5040 different 4 digit codes.
How many symbols can you make with a 7 LED grid?
In a 7 segment display, the symbols can be created using a selected number of segments where each segment is treated as a different element.When 1 segment is used, the possible positions are 7because it can be any of the 7 segments (7C1=7).When 2 segments are used, the number of possible combinations are 7C2=21.When 3 segments are used, the number of possible combinations are 7C3=35When 4 segments are used, the number of possible combinations are 7C4=35When 5 segments are used, the number of possible combinations are 7C5=21When 6 segments are used, the number of possible combinations are 7C6=7When 7 segments are used, the number of possible combinations are 7C7=1Adding the combinations, 7+21+35+21+7+1=127Therefore, 127 symbols can be made using a 7 segment display!
How many 9 number combinations using 0-9?
There are only 10 combinations. In each combination one of the 10 digits is left out.
How many two digit number combinations can you get using the number 1234 without repeating a digit?
There are twelve possible solutions using the rule you stated.
How many possible unique alpha numeric combinations are there using all letters for 4 characters?
im assuming that any charcter can be a number or a letter: (24letters*10 possible numbers)^(4 digits)= 3317760000 possible combinations.
Using 4 digits what is the total number of combinations for a 4 digit lock code?
If the digits can repeat, then there are 256 possible combinations. If they can't repeat, then there are 24 possibilities.
How many 4 digit combinations are there in the number 6000 using only 6 and 0?
There is only 1 combination.
