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With 5 bits, you can represent (2^5) different numbers, which equals 32. This includes numbers ranging from 0 to 31 in unsigned binary representation. If using signed binary representation (like two's complement), the range would be from -16 to 15, still allowing for 32 distinct values.
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How many different number can be represented using 5 bits?
Using 5 bits, a total of (2^5) different numbers can be represented. This equals 32, allowing for values ranging from 0 to 31 in unsigned binary representation. If signed representation is used (e.g., two's complement), the range would be from -16 to 15, still totaling 32 distinct values.
What decimal numbers are represented by this binary number 101?
101 = 5
Is -5 a irrational number?
No, -5 is not an irrational number. Irrational numbers are numbers that cannot be represented as the quotient of two integers. Since -5 is already an integer, it is rational.
How many bits do you need to represent months of the year?
Well, honey, to represent months of the year, you need at least 4 bits because you've got 12 months in a year, and you need 4 bits to represent numbers from 0 to 15. So, technically, you could do it with just 4 bits, but if you want to be fancy, you could use 5 bits for a more efficient representation.
How many number of bits are required to permit selection of 1 out of 32 equi-probable events?
5 bits, since 2 to the power 5 equals 32.
How many bits to represent twenty-six?
23 can be represented in binary as 10111 and would therefore require 5 bits to represent.
How many different number can be represented using 5 bits?
Using 5 bits, a total of (2^5) different numbers can be represented. This equals 32, allowing for values ranging from 0 to 31 in unsigned binary representation. If signed representation is used (e.g., two's complement), the range would be from -16 to 15, still totaling 32 distinct values.
What is the largest number that can be represented using 5 bits?
31 - it's binary equivalent is 11111
What decimal numbers are represented by this binary number 101?
101 = 5
If 88 MB is used out of 5 gb how many is left?
5 gb= 5*230 bits 88 mb= 88*220 bits Therefore if 88 mb is used out of 5 gb then = 5 gb - 88 mb bits are left = 5*2 30 bits - 88*220 bits = 220(5*210-88) bits = 220(5*1024-88) bits = 220*5032 bits = 5032 mb are left
How many bits or bytes required to store the robot?
40 bits or 5 byrtes
How many bits of mask are required to provide 30 host addresses?
5 bits
Is -5 a irrational number?
No, -5 is not an irrational number. Irrational numbers are numbers that cannot be represented as the quotient of two integers. Since -5 is already an integer, it is rational.
How many mega bits in 5 gig a bits?
http://www.google.co.uk/search?q=5+gigabits+in+megabits 5120 megabits in 5 gigabits
How many bits do you need to represent months of the year?
Well, honey, to represent months of the year, you need at least 4 bits because you've got 12 months in a year, and you need 4 bits to represent numbers from 0 to 15. So, technically, you could do it with just 4 bits, but if you want to be fancy, you could use 5 bits for a more efficient representation.
What are some rational numbers that are not integers?
1/2, 5/8, and 6/7 are some. Rational numbers are numbers that can be represented as fractions, so there are practically unlimited numbers of them.
What numbers equal 17 when one number is greater by 5?
If this refers to the SUM of two numbers then let the lesser number be represented by a. Then, a + (a + 5) = 17 : 2a + 5 = 17 : 2a = 12 : a = 6 So the two numbers are 6 and 11.
