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With 5 bits, you can represent (2^5) different numbers, which equals 32. This includes numbers ranging from 0 to 31 in unsigned binary representation. If using signed binary representation (like two's complement), the range would be from -16 to 15, still allowing for 32 distinct values.
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How many different number can be represented using 5 bits?
Using 5 bits, a total of (2^5) different numbers can be represented. This equals 32, allowing for values ranging from 0 to 31 in unsigned binary representation. If signed representation is used (e.g., two's complement), the range would be from -16 to 15, still totaling 32 distinct values.
What decimal numbers are represented by this binary number 101?
101 = 5
Is -5 a irrational number?
No, -5 is not an irrational number. Irrational numbers are numbers that cannot be represented as the quotient of two integers. Since -5 is already an integer, it is rational.
How many bits do you need to represent months of the year?
Well, honey, to represent months of the year, you need at least 4 bits because you've got 12 months in a year, and you need 4 bits to represent numbers from 0 to 15. So, technically, you could do it with just 4 bits, but if you want to be fancy, you could use 5 bits for a more efficient representation.
What is largest decimal number that can be stored using 5 bits of coding?
The largest decimal number that can be stored using 5 bits is 31. This is because 5 bits can represent binary numbers from 00000 (0 in decimal) to 11111 (31 in decimal). The maximum value is calculated as (2^5 - 1), which equals 31.
How many bits to represent twenty-six?
23 can be represented in binary as 10111 and would therefore require 5 bits to represent.
How many different number can be represented using 5 bits?
Using 5 bits, a total of (2^5) different numbers can be represented. This equals 32, allowing for values ranging from 0 to 31 in unsigned binary representation. If signed representation is used (e.g., two's complement), the range would be from -16 to 15, still totaling 32 distinct values.
How many bits required to represent -5?
To represent -5 in binary using two's complement, you first need to determine how many bits are required for the positive equivalent, which is 5. In binary, 5 is represented as 101. To accommodate the negative sign, you typically use at least 8 bits for clarity, which would represent -5 as 11111011 in two's complement. Therefore, at least 8 bits are needed to represent -5 in this format.
What is the largest number that can be represented using 5 bits?
31 - it's binary equivalent is 11111
What decimal numbers are represented by this binary number 101?
101 = 5
If 88 MB is used out of 5 gb how many is left?
5 gb= 5*230 bits 88 mb= 88*220 bits Therefore if 88 mb is used out of 5 gb then = 5 gb - 88 mb bits are left = 5*2 30 bits - 88*220 bits = 220(5*210-88) bits = 220(5*1024-88) bits = 220*5032 bits = 5032 mb are left
How many bits or bytes required to store the robot?
40 bits or 5 byrtes
How many bits of mask are required to provide 30 host addresses?
5 bits
How many mega bits in 5 gig a bits?
http://www.google.co.uk/search?q=5+gigabits+in+megabits 5120 megabits in 5 gigabits
Is -5 a irrational number?
No, -5 is not an irrational number. Irrational numbers are numbers that cannot be represented as the quotient of two integers. Since -5 is already an integer, it is rational.
How many bits do you need to represent months of the year?
Well, honey, to represent months of the year, you need at least 4 bits because you've got 12 months in a year, and you need 4 bits to represent numbers from 0 to 15. So, technically, you could do it with just 4 bits, but if you want to be fancy, you could use 5 bits for a more efficient representation.
What is largest decimal number that can be stored using 5 bits of coding?
The largest decimal number that can be stored using 5 bits is 31. This is because 5 bits can represent binary numbers from 00000 (0 in decimal) to 11111 (31 in decimal). The maximum value is calculated as (2^5 - 1), which equals 31.
