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With 5 bits, you can represent (2^5) different numbers, which equals 32. This includes numbers ranging from 0 to 31 in unsigned binary representation. If using signed binary representation (like two's complement), the range would be from -16 to 15, still allowing for 32 distinct values.
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How many different number can be represented using 5 bits?
Using 5 bits, a total of (2^5) different numbers can be represented. This equals 32, allowing for values ranging from 0 to 31 in unsigned binary representation. If signed representation is used (e.g., two's complement), the range would be from -16 to 15, still totaling 32 distinct values.
What decimal numbers are represented by this binary number 101?
101 = 5
Is -5 a irrational number?
No, -5 is not an irrational number. Irrational numbers are numbers that cannot be represented as the quotient of two integers. Since -5 is already an integer, it is rational.
How many bits do you need to represent months of the year?
Well, honey, to represent months of the year, you need at least 4 bits because you've got 12 months in a year, and you need 4 bits to represent numbers from 0 to 15. So, technically, you could do it with just 4 bits, but if you want to be fancy, you could use 5 bits for a more efficient representation.
How many number of bits are required to permit selection of 1 out of 32 equi-probable events?
5 bits, since 2 to the power 5 equals 32.
