With 5 bits, you can represent (2^5) different numbers, which equals 32. This includes numbers ranging from 0 to 31 in unsigned binary representation. If using signed binary representation (like two's complement), the range would be from -16 to 15, still allowing for 32 distinct values.
Using 5 bits, a total of (2^5) different numbers can be represented. This equals 32, allowing for values ranging from 0 to 31 in unsigned binary representation. If signed representation is used (e.g., two's complement), the range would be from -16 to 15, still totaling 32 distinct values.
101 = 5
No, -5 is not an irrational number. Irrational numbers are numbers that cannot be represented as the quotient of two integers. Since -5 is already an integer, it is rational.
Well, honey, to represent months of the year, you need at least 4 bits because you've got 12 months in a year, and you need 4 bits to represent numbers from 0 to 15. So, technically, you could do it with just 4 bits, but if you want to be fancy, you could use 5 bits for a more efficient representation.
5 bits, since 2 to the power 5 equals 32.
23 can be represented in binary as 10111 and would therefore require 5 bits to represent.
Using 5 bits, a total of (2^5) different numbers can be represented. This equals 32, allowing for values ranging from 0 to 31 in unsigned binary representation. If signed representation is used (e.g., two's complement), the range would be from -16 to 15, still totaling 32 distinct values.
31 - it's binary equivalent is 11111
101 = 5
5 gb= 5*230 bits 88 mb= 88*220 bits Therefore if 88 mb is used out of 5 gb then = 5 gb - 88 mb bits are left = 5*2 30 bits - 88*220 bits = 220(5*210-88) bits = 220(5*1024-88) bits = 220*5032 bits = 5032 mb are left
40 bits or 5 byrtes
5 bits
No, -5 is not an irrational number. Irrational numbers are numbers that cannot be represented as the quotient of two integers. Since -5 is already an integer, it is rational.
http://www.google.co.uk/search?q=5+gigabits+in+megabits 5120 megabits in 5 gigabits
Well, honey, to represent months of the year, you need at least 4 bits because you've got 12 months in a year, and you need 4 bits to represent numbers from 0 to 15. So, technically, you could do it with just 4 bits, but if you want to be fancy, you could use 5 bits for a more efficient representation.
1/2, 5/8, and 6/7 are some. Rational numbers are numbers that can be represented as fractions, so there are practically unlimited numbers of them.
5 bits, since 2 to the power 5 equals 32.