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How many positive integers less than 100 are divisible-by 3 5 and 7?
To find how many positive integers less than 100 are divisible by 3, 5, and 7, we first calculate their least common multiple (LCM). The LCM of 3, 5, and 7 is 105. Since 105 is greater than 100, there are no positive integers less than 100 that are divisible by all three numbers. Therefore, the answer is 0.
How many are the first 100 positive integers are divisible by 7?
(7*100*101)/2 = 35,350 jpacs * * * * * What? How can there be 35,350 integers in the first 100 integers? There are 14 of them.
Define prime numbers?
A prime number is a number in the set of positive integers such that it is only divisible by 2 unique numbers: itself, and 1. For this reason the first prime number is 2, not 1.
What is the sum of the first seven positive numbers?
The sum of the first seven positive INTEGERS is 28. The sum of the fisrt seven positive numbers is infinitesimally small.
What is the smallest positive integer that is divisible by each of the first ten counting numbers?
2520
What do the first 10 prime numbers have in common?
They're all positive integers under 30.
What is the sum of the first 100 positive integers divisible by 10?
First integer divisible by 10 is 10 itself .So the numbers are 10,20,30,40 and so onthe sum is10+20+30+40+....+990+100010(1+2+3+4+.....+99+100)10*100*101/250500
What is the sum of the first 60 positive integers?
The sum of the first 60 positive integers is 1830.
What is the sum of the first 500 positive integers?
The sum of the first 500 positive integers is: 125,250
What is the sum of the first ten positive integers?
The sum of the first ten positive integers is: 55
What is the sum of the first 30 positive integers?
The sum of the first 30 positive integers is: 465.
How many positive integers less than 1001 are divisible by either 2 or 5 or both?
To find the number of positive integers less than 1001 that are divisible by either 2 or 5, we use the principle of inclusion-exclusion. First, the count of integers divisible by 2 is ( \left\lfloor \frac{1000}{2} \right\rfloor = 500 ), and those divisible by 5 is ( \left\lfloor \frac{1000}{5} \right\rfloor = 200 ). The count of integers divisible by both 2 and 5 (i.e., by 10) is ( \left\lfloor \frac{1000}{10} \right\rfloor = 100 ). Thus, the total is ( 500 + 200 - 100 = 600 ). Therefore, there are 600 positive integers less than 1001 that are divisible by either 2 or 5.
