If no pair of lines is parallel and if each pairwise intersection is distinct, there will be 499500 points of intersection.
3 intersecting lines, because none of the three points are right angles.
4 points of intersection, meaning 4 lines
In a plane, only one.
There are 20 common points.
one solution
If no pair of lines is parallel and if each pairwise intersection is distinct, there will be 10 points of intersection.
If no pair of lines is parallel and if each pairwise intersection is distinct, there will be 6 points of intersection.
4
there are 4 intersecting lines
Two intersecting lines can always cover three non-collinear points.
A minimum of two.
Five intersecting lines can have a maximum of 10 points of intersection, assuming that no two lines are parallel and no three lines intersect at the same point. Each pair of lines can intersect at one unique point, and the number of ways to choose 2 lines from 5 is given by the combination formula ( \binom{5}{2} = 10 ). Therefore, with optimal conditions, the maximum number of intersection points is 10.